Im writing a script that will check which scripts are running. The script will run on a 5min loop and the status of the scripts will be written to the log. If any of the scripts arent running an email will be sent out.
At the min if all scripts are running an entry is made to the log saying so. If any are down an entry is made to the log saying tis and an email is sent out.
The problem is that the email sent out just sends out the name of the last script in AllScripts.txt(even if it is not down). I wish to have the script compare which scripts are not running against the list in my file and include these scripts in the email.
Ideally I would also like to list the scripts that are down in my log but I figure if I can get one working I'll be able to do the other.
Any info/help would be appreciated cos I have hit a bit of a block.
i know is not the perfect answer, but i think you better check out hobbit script for procs
it does exactly what you want, even better, you could use the client The Hobbit Monitor
fair enough.
i think you are over working with that script.
i would do like this (psudo code)
for how actually do all that stuff. well, i can think of these
PS
ps -whatevarOptionsForYourUnix > /tmp/tempile
"for each line" <-- i would use a rediction to a while
i think im in love with the "feeding from below" thingy :P
"grep the line"
just use grep $line /tmp/tempfile
"if we found it"
check for greps erturn code. i think that goes liek this
0 - grep found at least something
1= grep did not find anything
and you check if with
if [ $? -eq 0 ]
$? holds the return code of the last program/subshell spawned
-eq is an option for test that is read "equals" and aplies to integers
that would be the basic skeleton.
the decicion structures and stuff.
you can read alot more about bash and scripting here.
(Ħincluding test, internal bash variables, and redictions) Advanced Bash-Scripting Guide
Cheers. Im looking into that.
At the min im writing my grep to output to a tmp file. I can get this working but includes my actual grep in the output too. I know -v is used to hide the grep but not sure how it should look in a script. Heres what I got:
Cheers. Im looking into that.
At the min im writing my grep to output to a tmp file. I can get this working but includes my actual grep in the output too. I know -v is used to hide the grep but not sure how it should look in a script. Heres what I got:
why you grep for chk?
Quote:
Originally Posted by runnerpaul
I have tried:
ofcorse, the way to doit is how you did it next
Quote:
Originally Posted by runnerpaul
and:
Both created an empty tmp file.
Got any suggestions?
ig the first grep donst find chk, then the second one is taking out the only match.
I tried to run the following commands in my shell script.
This command works fine for me:
ssh -n "${username}"@"${hostname}" "grep WARNING ${serverhome}/${serverlog} | wc -l"
The result is:
1548
However when i try to run a similar one:
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