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Perl regex question

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# 8  
Old 07-18-2008
Quote:
Originally Posted by KevinADC
split() is a regexp.
split can split on regexp. In OP's case, it doesn't have to be a regexp. just split on dots, that's what i meant.
Code:
$file="scores.234506.csv";
$myarray = (split(/\./,$file))[1];
print $myarray;

# 9  
Old 07-18-2008
The first argument to the split function is a regexp. Its not that split can split on a regexp, it does split on a regexp. Your suggestion is still a good one but your example returns the wrong results to $myarray. He wants the [0] position returned instead of [1];
# 10  
Old 07-18-2008
Quote:
Originally Posted by KevinADC
The first argument to the split function is a regexp. Its not that split can split on a regexp, it does split on a regexp.
yes no doubt about that. I was referring to the expression itself. A dot escaped and not something like ^(\w+)\.\d{6}\.csv$ where you have all those syntaxes.
Quote:
Your suggestion is still a good one but your example returns the wrong results to $myarray. He wants the [0] position returned instead of [1];
wrong or right, doesn't matter. the OP has got to explore for himself what is right or wrong.
# 11  
Old 07-18-2008
Quote:
I was referring to the expression itself.
Ahhh..... sorry, I misunderstood you.
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