Sponsored Content
Full Discussion: Perl regex question
Top Forums Shell Programming and Scripting Perl regex question Post 302216103 by KevinADC on Friday 18th of July 2008 02:49:32 AM
Old 07-18-2008
The first argument to the split function is a regexp. Its not that split can split on a regexp, it does split on a regexp. Your suggestion is still a good one but your example returns the wrong results to $myarray. He wants the [0] position returned instead of [1];
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

regex question

hi, i got a problem with understanding regular expressions. what i wanna do is scanning the wtmp logfile for ips and if a specific ip is echoed id like to be a part of a text to be assigned to it. the scanning is done with #! /bin/bash cat wtmp | strings | egrep -o "+\.+\.+\." | sort -u... (6 Replies)
Discussion started by: rocketkids
6 Replies

2. Shell Programming and Scripting

regex question

Hi I have a question on regex There is a line in a script like my_file="$(echo SunMonTueWed | sed "s//_&g") " My question what does the expression _&g do. Obviously in this example the output is _Sun_Mon_Tue_Wed Another question can i use some trick to get the result like... (3 Replies)
Discussion started by: xiamin
3 Replies

3. Shell Programming and Scripting

regex question

Hi, im sure this is really simple but i cant quite figure it out. how do i test against a word at the beginning of the line but up to the point of a delimiter i.e. ":" for example if i wanted to test against the user in the /etc/passwd file peter:x:101:100:peters account:/var/peter:/bin/sh ... (3 Replies)
Discussion started by: hcclnoodles
3 Replies

4. Shell Programming and Scripting

Perl regex question

$var=~ s#(\n?<a>.*?</a>\n)##s $pat=$1 Recently i came across this bit of a code. Can someone please explain the function of these two line? (5 Replies)
Discussion started by: King Nothing
5 Replies

5. Shell Programming and Scripting

perl: question about the regex "=~"

Hello all Is there a "not" reversal method for the =~ regex thingy in perl ? for example, in the snippet below, i have placed a ! in front of the =~ to "not it".. although it quite obviously doesn't work and is just me trying to get across the question in a way that somebody may understand :o... (2 Replies)
Discussion started by: rethink
2 Replies

6. Shell Programming and Scripting

Question on regex with * and .

I have a basic question regarding * and . while using regex: # echo 3 | grep ^*$ 3 I think I understood why it outputs "3" here (because '*' matches zero or more of the previous character) but I don't understand the output of the following command: # echo 3 | grep ^.$ # I thought I... (7 Replies)
Discussion started by: mirage
7 Replies

7. Shell Programming and Scripting

Converting perl regex to sed regex

I am having trouble parsing rpm filenames in a shell script.. I found a snippet of perl code that will perform the task but I really don't have time to rewrite the entire script in perl. I cannot for the life of me convert this code into something sed-friendly: if ($rpm =~ /(*)-(*)-(*)\.(.*)/)... (1 Reply)
Discussion started by: suntzu
1 Replies

8. Shell Programming and Scripting

Regex Question

Hi I am trying to match lines having following string BIND dn="uid= putting something like this is not working : /\sBIND dn="uid=/ Any suggestion. Thanks. John (9 Replies)
Discussion started by: john_prince
9 Replies

9. Shell Programming and Scripting

Perl regex question

Hi Guys, I am trying to work out the regular expression that I would need to capture the below information. I need to find the word SAC followed by using the data thats contained on the next line. I have other expressions that i have configured but none are where the output is on two... (2 Replies)
Discussion started by: mutley2202
2 Replies

10. Shell Programming and Scripting

Perl, RegEx - Help me to understand the regex!

I am not a big expert in regex and have just little understanding of that language. Could you help me to understand the regular Perl expression: ^(?!if\b|else\b|while\b|)(?:+?\s+){1,6}(+\s*)\(*\) *?(?:^*;?+){0,10}\{ ------ This is regex to select functions from a C/C++ source and defined in... (2 Replies)
Discussion started by: alex_5161
2 Replies
RE_COMP(3)						     Linux Programmer's Manual							RE_COMP(3)

NAME
re_comp, re_exec - BSD regex functions SYNOPSIS
#define _REGEX_RE_COMP #include <sys/types.h> #include <regex.h> char *re_comp(char *regex); int re_exec(char *string); DESCRIPTION
re_comp() is used to compile the null-terminated regular expression pointed to by regex. The compiled pattern occupies a static area, the pattern buffer, which is overwritten by subsequent use of re_comp(). If regex is NULL, no operation is performed and the pattern buffer's contents are not altered. re_exec() is used to assess whether the null-terminated string pointed to by string matches the previously compiled regex. RETURN VALUE
re_comp() returns NULL on successful compilation of regex otherwise it returns a pointer to an appropriate error message. re_exec() returns 1 for a successful match, zero for failure. CONFORMING TO
4.3BSD. NOTES
These functions are obsolete; the functions documented in regcomp(3) should be used instead. SEE ALSO
regcomp(3), regex(7), GNU regex manual COLOPHON
This page is part of release 3.27 of the Linux man-pages project. A description of the project, and information about reporting bugs, can be found at http://www.kernel.org/doc/man-pages/. GNU
1995-07-14 RE_COMP(3)
All times are GMT -4. The time now is 08:42 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy