Shell Programming and Scripting

This is what I need (I don't know the amount of lines in my accesslist), but I also don't know the nale of the next accesslist...
So it should print all lines starting from "ip access-list extended MyAccessList" until it finds a line that doesn't start with remark or permit or deny. That is the only way to know my access-list is ended (access-lists can only start with these 3 words)...
Thanks for the help so far

So:

Code:

awk '/^ip access-list extended/{f=4}f&&f--' file

Could you post bigger sample and the desired output?

...
ip access-list extended MyAccessList
remark Do not allow Jones subnet to telnet out
deny tcp host 171.69.2.88 any eq telnet
remark Do allow me to telnet out
permit tcp host 171.69.2.89 any eq telnet
ip access-list extended YourAccessList
remark this is your security rule
permit host 192.168.0.1 any
...



I want to print the content of MyAccessList like this:

ip access-list extended MyAccessList
remark Do not allow Jones subnet to telnet out
deny tcp host 171.69.2.88 any eq telnet
remark Do allow me to telnet out
permit tcp host 171.69.2.89 any eq telnet




In pseudo-code, this would be something like:

find linenumber with word "MyAccesslist"
while linenumber+1 contains "remark/deny/permit"
print linenumber+1
wend

Hope this helps to clarify...

Try this:

Code:

awk '
/MyAccessList$/{f=1}
f&&/^ip access-list extended/{exit}
f' file

Regards

I don't have my BSD machine here to test now, but I don't think it will work.
From what I can read, you check until you find a line that starts with "ip access-list extended", but the end of the accesslist can be anything (except a line that starts with permit/deny/remark; this would mean that it is still the access-list)
So my guess is that I need to trigger these 3 words; if not found, the access-list has ended...

Code:

awk '!/deny|remark|permit|MyAccessList/{exit}
/MyAccessList/,0' file