Shell Programming and Scripting

hi,

I am new to scripting and need your help to debug .

Here is my goal, I need to collect text,validate it and say if there is any error .below is the code


validate_fn()
{
awk ' ....
END {

if(condition)
return 0
else
return 1
}' "$3"
}

Script1=/usr(Path) #my main script
paramter1="$1"
parameter2="$2"

a = $(Script1 log -t "$parameter1" "$parameter2") (# to store the text that I will be validating )

if($(validate_fn $a)== 1)then
{
echo"** error**">$2
exit 1
}
fi

exit 0


Here

I am trying to send the text to the function and if the condition is met the present script has to exit 0 else it has to echo error and exit 1 but the script is always exiting with with '0'.

The $(...) construct captures the output, not the return code, of the awk script. Make it print a value, or use a different construct. The simple if command is the standard way to test an exit code.

Code:

if awk 'END { exit rand() }' </dev/null
then
  echo exit code from awk was 0
else
  echo exit code from awk was 1
fi

(My mawk demands that I use exit rather than return if I'm not returning from an awk function. That is probably more correct even if your awk doesn't have the same requirement.)

(The random function returns a number between 0 and 1, and it seems that it will always be truncated to an integer zero, but this is just a lousy example anyway.)

ooh...

Here my present script is being called by a script, the deal is

My script (say script2) should exit out with 1 or 0.

Is there any other way?

so that

1) Get the text from script1 (Script1 log -t "$parameter1" "$parameter2")

2) validate it with the function (validate_fn )

3) echo error message depending on the result from the validation function