select action in "blabla" "blabla" "quit"
do
case $action in
"blabla")
somecommand
;;
.... for each possible command a $action
"quit")
break
;;
*)
print "this is not an option, try again"
;;
esac
done
ok i hate to sound like a complete lamen, but could you spell it out for me a bit better than that for me please. I am a complete beginner and dont really know much about it.
It's easier to understand when you format your code so that's more manageable to work with and read ...
Code:
select action in "blabla" "blabla" "quit"
do
case $action in
"blabla") echo "I was passed blabla."
echo "Now executing a command..."
somecommandhere ;; #.... for each possible command in $action
"quit") break ;;
*) print "this is not an option, try again" ;;
esac
done
The select statement reads the values after 'in' ... "blabla" "blabla" "quit" .
Then selects each one in turn and passes the value to $action to use within the select statement. $action is used in the case statement, here the value is compared to those listed values contained within the case statement and if a match is made, executes the code attached to that match. If the value of $action doesn't match any value contained within the case statement, then it is passed to (or rather picked-up by) the statements associated with '*'.
Very new to the Korn Shell, but I've been looking up loops online and it seems this should work. I'm just trying to convert an ip range in variables $A and $B and iterate the individual ip's out to new lines. Unfortunately I get {152..155} instead of 152, 153, 154, and 155.
# for i in {$A..$B};... (8 Replies)
I have a script that loops through a list of users to list files owned by these users
for u is `cat users.list`
do
echo $u >> result.out
find /home -user $u >> result.out
find /var -user $u >> result.out
find /opt -user $u >> result.out
find /usr -user $u >> result.out
done
an so... (3 Replies)
#!/bin/bashi
function userrecord() {
read -p "please enter a number: " a
clear
output=$(grep -w "$a" appraisalrecord)
b=$(echo $a | tr -dc )
if ]; then
echo -e "accepted\n"
else
echo -e "The input must be a numerical number\n"
userrecord
fi
if ]; then
echo -e "the ID has... (2 Replies)
for i in `seq 1 10 ` ; do
printf $i '\n';
done
gives me this:
1234567891064mbarch ~ $ (output followed by bash prompt) :(
I've tried so many ways to create a newline at the end. Does anyone have any ideas.. Thanks in advance. Sorry (7 Replies)
good afternoon forums.
i have a problem that ive been trying to work out all morning and cant seem to get my head around it.
what i have in my script is individual letters saved in different variables. so if the word unix was saved then 'u' would be stored in the variable 'wvar1' 'n' in 'wvar2'... (7 Replies)
I'm trying to understand if it's possible to create a set of variables that are numbered based on another variable (using eval) in a loop, and then call on it before the loop ends.
As an example I've written a script called question (The fist command is to show what is the contents of the... (2 Replies)
Hi guys,
I'm trying to loop through a number of files that is set by whatever is in a field.
eg.
The idea is to split FILELIST down into fields, it could contain 1 - 999 fields and it's bar delimited.
I thought simple, count the number of fields in the field and then loop... (1 Reply)
Hi there,
I have written a script to clear out log files from the var/tmp dir. It works up to a point. What I needed to do was to exit the script if there was no files to be deleted. I can get this working on a test script but when I implement it into my program it errors out with a `then` not... (3 Replies)
Here it wont terminate unless i take the not of my statement
#!/bin/bash
grabXML
parseXML
TAIL=5
#"$(cat dailyCasLog | tail -n 1)"
COUNT=200
LINE=5
#"$(cat dailyCasLog | head -n $COUNT | tail -n 1)"
echo $TAIL
echo $LINE
while ($LINE!=)
do
#$LINE">>currentLine
folderMaker
... (0 Replies)
05-13-2008
