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Shell Programming and Scripting

loop problems...

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# 1  
Old 05-27-2011
loop problems...
Code:
 #!/bin/bashi
function userrecord() {
read -p "please enter a number: " a
clear
output=$(grep -w "$a" appraisalrecord)
b=$(echo $a | tr -dc [:digit:])
if [[ "$a" = "$b" ]]; then
echo -e "accepted\n"
else
echo -e "The input must be a numerical number\n"
        userrecord
fi
if [[ -z $a ]]; then
echo -e "the ID has already been taken\n"
        userrecord
fi
}
userrecord

hi everything is fine but when typing in a character like two the second time it wont loop it back it just stays at the start, do u know whats wrong ?
# 2  
Old 05-27-2011
Put set -x 2nd line of script or #!/bin/bash -x to analyze.

I don't see any loops, just if then else.
What are you trying to achieve ?
# 3  
Old 05-27-2011
Quote:
#!/bin/bashi
Might be a paste error but there are two typos on this line (leading space and "bashi" not "bash").

The "loop" is where "userrecord" calls itself.

I too can't follow what the script is meant to do.

---------- Post updated at 17:18 ---------- Previous update was at 17:14 ----------

Quote:
function userrecord() {
Mixture of syntax here. There are two distinct ways of defining a function. This has blended them both.

This is enough:
Code:
userrecord() {

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