Shell Programming and Scripting

my friend has quized me.. I'm very new to scripts but I know I'm somewhat close

any help would be a major help..
here is the script

ex

shell program, hello, to display the phrase "hello world" 50 times (script should verify the

count) . Do not use a for loop! (hint should show hello world 1 ..... hello world 50 )

i put this

#!/bin/bash

count=1
max=50

while [ $count -le $max ] // a test of a condition -le another value
do
echo "Hello world $count"
let count=count+1

I still get a error.

any help would be nice thanks

airmax_sk@yahoo.com

You were on the right track.
However your comment syntax was wrong & you needed to end the while loop with "done"...

Code:

#!/bin/bash

count=1
max=50

while [ $count -le $max ] ## a test of a condition -le another value
do
echo "Hello world $count"
let count=count+1
done

Cheers,
Cameron

yah it gets a bunch of hellos out there


I must have forgot about the done command. no systex error.

i thought I put that on the command thanks for help cameron

Hi,

Without using any loops you can get the same output. Just give a try on it.

Code:

yes "hello world" | head -50| grep -n "hello world" | awk -F: '{print $2" "$1}'

Regards,
Chella

An awk trick:

Code:

awk 'BEGIN{$50=OFS="\nHello world";print}'|awk '!/^$/ {print $0,NR-1}'

Neat trick Klashxx.