search for lines in a file


 
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# 8  
Old 04-22-2008
Code:
grep -l "ALL MATCHING RECORD COLUMNS MATCHED (Baseline and Regression File)" file | \
xargs grep -l "Total Mismatched Records (Baseline File): 0" | \
xargs grep -l "Total Mismatched Records (Regression File): 0"

# 9  
Old 04-22-2008
Quote:
Originally Posted by shalua
neither worked!!

In both cases it hangs, looks like some syntax issue. any further suggestions !!

neither worked!!

also my script is a ksh script.

The code works fine on sh, bash, and ksh, and tested on different platforms ( GNU and other ), according to your initial request.

The command that you're using :

Code:
sed -n -e '/BBB/p' -e '/AAA/p' emp.dat | sed -n '$='

will give you a count of the lines, but it won't tell you if one of the lines is missing, ( its exit status will be 0 if only one line is found, out of three that you're searching for ), and this contradicts your first requirement:

Quote:
I want to check if all 3 lines exist or not, meaning an AND condition.
There is not enough clarity in your request. Anyway, if you want to get a count of your lines you could modify my code, ( using grep -c and assigning its output to variables, and summing them up), or using other tools as well.

All depends on your final requirements.
# 10  
Old 04-23-2008
Hi Rubin

Thanks for getting back!! My requirements is still the same. Since the grep logic didn't work for me, I started trying the sed logic and I thought I can check if the count returned is 3.

Anyways, I carefully looked at my grep code again, there was some syntax issue, it is working now. Many Thanks for your time!!

Thanks to all who contributed!!
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