Shell Programming and Scripting

Greetings

I have the following 2 scripts.

If I run script devput from the commandline. everything is fine.

However I am now trying to write a wrapper script that allows me to provide a file with the files I want to devput. This doesnt work as it does not seem to recognise the parameters?

Could anyone explain why? I am doing my own head in!

mput script

#!/usr/bin/ksh
LISTFILE=$1
comments=$2
mrs=$3

tty >/dev/null

# Loop over LISTFILE
while read FILENAMEdo
devput ${mFILENAME} -y "${comments}" -m ${mrs}
done < $LISTFILE

devput

#!/usr/bin/ksh
typeset -Z6 mrs

FILENAME=$1

shift
while getopts m:y: OPTION "$@" 2>/dev/null
do
case ${OPTION} in
m) MRS=${OPTARG};;
y) COMMENTS=${OPTARG};;
*) print ${USAGE}
exit 1
esac
done

echo "FILENAME: ${FILENAME}"
echo "COMMENTS: ${COMMENTS}"
echo "MRS : ${MRS}"

Results from command line

devput listfile -y "simon test" -m 009299
FILENAME: listfile
COMMENTS: simon test
MRS : 009299

Results from mput
mput listfile "simon test" 009299
FILENAME: file2
COMMENTS: "simon
MRS :

WHY WHY WHY????

I have been trying all day. I am sure this is simple, but I cant see the wood for the trees.

Please help a frustrated man again

Cheers
Si

Hi, modify 1st script:

Code:

#!/usr/bin/ksh
LISTFILE=$1
comments=$2
mrs=$3

tty >/dev/null

# Loop over LISTFILE
while read FILENAME 
do
devput ${FILENAME} -y "${comments}" -m ${mrs}
done < $LISTFILE

Cheers Clash but why is that??

Still it works I can go home with a on my face.

Nice one. really appreciate that!