Shell Programming and Scripting

using sed print the lines that have more than 10 characters, of each file. the files arre given as parameters. i did this:

#!/bin/sh

a=0
zece=10
if [ $# -eq 0 ]
then echo "An error occured regarding the parameters. "
else
for i in $@
do
if [ ! -e $i ]
then echo "The file does not exist. "
else
cat $i | cut -c 0- | while read l
do
echo $l > andrei.txt
a=`wc -c andrei.txt`
if [ $a -gt $zece ]
then sed -f exe.txt andrei.txt
fi
a=0
done
fi
done
fi

but i get an error to the last if: too many parameters. what is wrong?

With "wc -c andrei.txt" you get two columns as output, the number of columns and the name of the file.
Try something like:

Code:

a=`wc -c andrei.txt|cut -d" " -f1`

or

Code:

a=`cat andrei.txt|wc -c`

Regards

thank you very much...it works...i didn't know that...

Code:

 # wc -c < andrei.txt
214

YES, but sometimes I have trouble with what's called "Professional blindness"

Regards

Code:

sed -n '/........../p' files ...

Code:

perl -nle 'print if (length()>10)' files ...

The problem with the if is that you have the ! inside the [ ], it should be outside.