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param with awk

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# 1  
Old 03-28-2008
param with awk
Hi All,

I have this script:

#!/bin/ksh
lsvg -l $1|grep -v $1:|grep -v LV|awk '{print "mklvcopy ",$1," 2 $2 $3"}'

I want to pass three param with "vg2 hdisk1 hdisk2" but the output is "mklvcopy lv1 2 $2 $3". I want to pass the hdisk1 and hdisk2 and not the $2 and $3.

Please help!

Thanks in advance,
itik
# 2  
Old 03-28-2008
try this:
Code:
lsvg -l $1|grep -v $1:|grep -v LV|awk -vp1=$1 -vp2=$2 -vp3=$3 '{print "mklvcopy "p1" 2 "p2" "p3}'

# 3  
Old 03-28-2008
Might as well fix those dreadful Useless Uses of Grep | Awk.

Code:
lsvg -l "$1"| awk -vp1="$1" -vp2="$2" -vp3="$3" '!/LV|'"$1"'/{print "mklvcopy "p1" 2 "p2" "p3}'

Last edited by era; 03-28-2008 at 04:00 PM.. Reason: As long as we are discussing style, properly quote everything
# 4  
Old 03-28-2008
Actually, here's the correct one:

lsvg -l $1|grep -v $1:|grep -v LV|awk -vp2=$2 -vp3=$3 '{print "mklvcopy "$1" 2 "p2" "p3}'

If I use the above code, it will give me the vg parameter and not the lv.



Cool! Thank you guys.
Last edited by itik; 05-07-2008 at 12:18 PM..
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