how to extract paragraphs from file in BASH script followed by prefix ! , !! and !!!
I]hi all
i am in confusion since last 2 days
i posted thraed yesterday and some friends did help but still i couldnt get solution to my problem
let it be very clear
i have a long log file of alkatel switch and i have to seperate the minor major and critical alarms shown by ! , !! and !!! respectively
rm old alarm* files
will read an input file called alarms
put any beginning undefined lines into alarm
read thru the file, and based on ! or !! or !!! determine output file
write line to case'd filename
Note: once an alarm file is set, everything will be written there until a new alarm file is calculated.
#! /bin/bash
rm alarm alarm1 alarm2 alarm3
al_fl="alarm"
while read alt
do
al_pr=$(echo $alt | cut -d" " -f1)
case "$al_pr"
in
'!') al_fl="alarm1";;
'!!') al_fl="alarm2";;
'!!!') al_fl="alarm3";;
*) ;;
esac
# echo "$al_pr" "$al_fl"
echo "$alt">>"$al_fl"
done < alarms
but the problem is this , i have to deal with a log file keeping alarms of dated dec,07-jan 08
i have to extract these alarms entry by entry ,along with the contents it have ,to their respective files
(example of file given above)
i must have to take input from a file and then sort it and redirect respective paragraghs of log to that particular file e.g. ! to minor alarm file and so
i havnt successful in acheiving input from file and to sort by !!! , !! and !.
plz help me to come to solution of my problem
i want to extract paragraphs line following prefix ! , !! and !!!
i tried so mant times but i coldnt do it
file sample is in given above thraed
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