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Shell Programming and Scripting

remove part of a line

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# 15  
Old 02-06-2008
Quote:
Originally Posted by vino
Code:
sed -n -e "s/.*\/\([^\/]*\.proc\)\$\$.*/\1/p" input.txt

This looks simpler

Code:
sed -ne "s/\$\$.*//p" input.txt | xargs basename

# 16  
Old 02-06-2008
An awk:
Code:
awk '/\.proc/{sub(/\$.*/,"",$0);print}' RS='/' file.txt

# 17  
Old 02-06-2008
try this also
let
cat dot.txt
/foldera/database/procedure/a.proc$$/version1/2
/folderb/database/procedure/proj1/b.proc$$/version2/2
/folderb/database/procedure$$/proj1/version3/45
$
$ cat dot.txt | awk -F"." '/.proc\$\$/ {print $1".proc"}'
/foldera/database/procedure/a.proc
/folderb/database/procedure/proj1/b.proc
Last edited by manas_ranjan; 02-06-2008 at 08:33 AM.. Reason: changed $0 to $1
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