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help required for replacing text in vi

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# 1  
Old 01-25-2008
help required for replacing text in vi
Hi
Any one pls give me command in vi to replace /opt/usr with /home/reddy/dump .... i tried escaping / with \ bt its not working...


thanks in advance
# 2  
Old 01-25-2008
At the : prompt type

Code:
#/opt/usr#/home/reddy/dump#

# 3  
Old 01-25-2008
In vi:

:%s#\/opt\/usr#\/home\/reddy\/dump#g


QED! (quite easily done!)
# 4  
Old 01-26-2008
:%s_/opt/usr_/home/reddy/dump_g

u can use anydelimiter ...since ur string cntains too many slashes, therefore to avoid escaping all the slashes and messy syntex... this 1 'll be the simplest.

Anchal.
# 5  
Old 01-26-2008
@dewets : why u again esacpe the slashes... if u alreadyusing delim as "#".
i dont think its needed...
is there any other reason..... correct me if i m wrong...
# 6  
Old 01-26-2008
Quote:
Originally Posted by anchal_khare
@dewets : why u again esacpe the slashes... if u alreadyusing delim as "#".
i dont think its needed...
is there any other reason..... correct me if i m wrong...
Yes, thats correct.

When '#' is used as delimiter no need to use '/' as '\/'

but using '#' when the patten contains '/' adds more readability
# 7  
Old 01-26-2008
better use perl search and replace.

Quote:
perl -i -pe 's/old pattern/new pattern/g' filename
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