Displaying current user process

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# 8  
Old 12-16-2007
Ps with awk

You could do this...
cat felix.whoals | awk '
cmd=sprintf("ps -au %s",$1);
print cmd
system (cmd);
# 9  
Old 12-16-2007
So this cannot be solved without awk and sed? I do not want to use these two commands because I want to use the long way to do it. Do you have another solution without using awk?
# 10  
Old 12-16-2007
Originally Posted by felixwhoals
Well because when I do head -1 abc it gives me a username. therefore when I do ps -au head -1 abc, I should get an answer shouldn't I?

May I know how can I solve this problem?
Programs are run by specifying a name and some optional arguments and additionally some IO redirection.

In the first case you refer to program called "head" with arguments "-1" and "abc".

In the second case you refer to a program called "ps" with arguments "-au", "head", "-1" and "abc".

Do you mean
ps -au `head -1 abc`

so that the output of "head -1 abc" becomes a command line argument?
# 11  
Old 12-16-2007
Originally Posted by felixwhoals
I have a file with my username in it.
So if I type cat filename, I get felix.whoals
TO show the current process that I am doing, I need to type ps -au felix.whoals
ps -au `cat filename`

# 12  
Old 12-16-2007
So many ways, but this is the simplest

There might be 1000 good ways to do this, but you probably won't find one any better, shorter, or less complicated. The example can be done in one line, just takeout the newlines and the print statement. If you want to print the cmd, the statement probably needs to look like: print(cmd); (notice the parens and semi colon).
# 13  
Old 12-16-2007

ps -au `head -1 abc` where head -1 abc gives me an argument (username) and then I could use it to get the process running for the current username.

Do you know the way to fix it?
# 14  
Old 12-16-2007


will give the current user

ps -au `echo $LOGNAME`

would do want you want but can be simplified to

ps -au $LOGNAME

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