Shell Programming and Scripting

Hello, does anyone know how sed can convert a file like the one shown below.

I have a file that contains data like this:

Nov-12-2007
line1
line2
line3
Nov-13-2007
line5
line6
Nov-14-2007
line8
line9
line10

and what I want is this:

Nov-12-2007,line1
Nov-12-2007,line2
Nov-12-2007,line3
Nov-13-2007,line5
Nov-13-2007,line6
Nov-14-2007,line8
Nov-14-2007,line9
Nov-14-2007,line10

Any help would be appreciated.

Thanks

Code:

#!/bin/perl -w
$date="";
while (<>) {
  if (/^(\w\w\w\-\d\d\-\d\d\d\d)$) { $date=$1 }
  else { print ${date},$_ }
}

Thank You Smiling Dragonl
I had to add a delimiter "/" to the end of the search search string on line 4 before it would run on my machine but it works great.
Here is the revised code:

#!/bin/perl -w
$date="";
while (<>) {
if (/^(\w\w\w\-\d\d\-\d\d\d\d)$/) { $date=$1 }
else { print ${date},$_ }
}

oops, well spotted!

Hi

code:

Code:

awk '
$1 ~ /-[0-9][0-9]-/ {c=$1}
$1 !~/-[0-9][0-9]-/ {print c","$0}
' filename