Shell Programming and Scripting

currently i am doing a project where in i am creating files everyday with a name xyz_date for e.g. xyz_20071010,xyz_20071011 ... in this fashion.so at a particular point of time i need only 31 days of data.suppose we are executing the code today then we will have only 31 days data present and 32day's data(file) will be removed.
at a particular date i need only files with today() and today()-31.today()-32 will be removed.how can i write such a script.

Something like

Code:

find . -type f -mtime +31 -exec rm -f {} \;

sorry friend coundnot get the code..
how can it find the path where the files are located and the format is YYYYMMDD.the naming convention of the file is
dab_unload_20071022
dab_unload_20071023
if we are running it on 24 the then 20071024 - 32 date should be removed..please explain a bit detail

i have another doubt how can we find only the file names in another file located in a different path.means past 30 days file names i need in another path.suppose today is 25-oct-2007 then i need files from 26th sep to 25 th oct.
the names should be
dab_unload_20071025
dab_unload_20071024
...
dab_unload_20070925

Code:

find /path/to/files -type f -name "dab_unload*" -mtime +31 -exec rm -f {} \;

this script only removes the content of the file..but the file remains as it is.please help me how can i remove the total file

sorry....my file was empty...
this code is not working...my req is to delete a file DAB_Unld_20071109 .
if today is 9th Nov then remove it,,