awk getline help maybe?

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Old 10-24-2007
awk getline help maybe?

hello collegues,

I am attempting to use awk to search file1 (serverlist.csv) from each row with file2 (supported.txt). If the is no entry exists in serverlist then output to a file called notsupp.out if there is an entry output to supp.out

I can do this with basic shell scripting however would like to use awk and understand the syntax as the file I am searching is rather large.

here is what I got so far:

awk 'BEGIN{while (getline LINE < "serverlist.csv") > 0);{print LINE}' supported.txt

I would have expected this to print all lines that match however everthing prints :-(

any help is greatly appreciated!


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IGAWK(1)							 Utility Commands							  IGAWK(1)

igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins ( Free Software Foundation Nov 3 1999 IGAWK(1)