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# 1  
Old 10-08-2007
Question print selected lines

Hi everybody:
I try to print in new file selected lines from another file wich depends on the first column.

I have done a script like this:

	lines=( "1" "2" "3" "4" "5" "6" "7" "8" "9" "10" "11" "21" "31" "41" "51" "55" "57" "58" )
	for lines in ${lines[@]}
	awk -v  target=$lines  ' $1 == target print $0 ' file1 >> file2

But I have the next error:

./ 42: Syntax error: "(" unexpected ------ where the line 42 correspond when I declare the array "lines"

Any suggestion?. Thanks in advance Smilie
# 2  
Old 10-08-2007
What shell are you using? In KSH the following works:

set -A lines = 1 2 3 4 5 6 7 8 9 10 11 21 31 41 51 55 57 58
print ${lines[12]}

will print '21'
# 3  
Old 10-08-2007
Thanks for your reply. I usually use the sh shell. Smilie
# 4  
Old 10-08-2007
I don't think the bourne shell supports arrays.
# 5  
Old 10-08-2007
Hi again:
I have seen at "Advanced Bash-Scripting Guide" by Mendel Cooper that it is possible to use arrays on bourne shell scripts.
# 6  
Old 10-08-2007
Bash is the bourne again shell, the newer version of the bourne shell, or sh.

If you want bash, start your script with #!/bin/bash otherwise if no shell is selected sh will be used, and that doesn't support arrays as far as I know.
# 7  
Old 10-08-2007
Smilie I have done, I have changed:




and now it works correctly. Thnaks a lot. Smilie

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