problem using awk


 
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# 1  
Old 10-02-2007
problem using awk

Hi, Anyone know why i get this error?

+ awk -F, '{if($5=="x" && $6=="y" && $10=="z")print $0}' file.data
awk: syntax error near line 1
awk: bailing out near line 1

This is the output from a shell script that can be resumed like...

set -x
fich_dat=file.data
variable1=x
variable2=y
variable3=z
awk -F, \''{if($5=='\"$variable1\"' && $6=='\"$variable2\"' && $10=='\"$variable3\"')print $0}'\' $fich_dat



The most strange is that if i copy paste:
awk -F, '{if($5=="x" && $6=="y" && $10=="z")print $0}' file.data
in the unix console, it works.

The UNIX system is:
Sun Microsystems Inc. SunOS 5.9
# 2  
Old 10-02-2007
Try this syntax :
Code:
set -x
fich_dat=file.data
variable1=x
variable2=y
variable3=z
awk -F, -v V1="$variable1" -v V2="$variable2" -v V3="$variable3" \
'{if($5==V1 && $6==V2 && $10==V3)print $0}' $fich_dat

In case of error, try to use nawk instead of awk

Jean-Pierre.
# 3  
Old 10-02-2007
merci! vous Ítes une machine!

This code works:

nawk -F, -v V1="$variable1" -v V2="$variable2" -v V3="$variable3" '{if($5==V1 && $6==V2 && $10==V3)print $0}' $fich_dat
# 4  
Old 10-02-2007
or a bit more terse:
Code:
nawk -F, -v V1="$variable1" -v V2="$variable2" -v V3="$variable3" '$5==V1 && $6==V2 && $10==V3' $fich_dat

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