## generate level numbers

generate level numbers
# 1
09-19-2007
generate level numbers

Hi...

I have a sequence of jobs and its predecessors..

Input

Job_Name Predecessor
A NULL
B1 A
B2 A
B3 B1
C B3
C B2

So based on these i have to generate the level Number
What i mean is

Let A be level 1
for B1 to happen it should have done A
so B1 level is A+1 = 1+1 = 2
and same for B2 it should have done A
so B2 level is A+1 = 1+1 = 2
for B3 to happen it should have done B1
so B3 level is B2+1 = 2+1 = 3

but for C to complete it should have done B2 and B3
so C is max(B2,B3)+1
C=max(2,3)+1=4

so the final out put should be

A NULL 1
B1 A 2
B2 A 2
B3 B1 3
C B3 4
C B2 4

I am not able to code the logic..

 pbsrinivas View Public Profile for pbsrinivas Find all posts by pbsrinivas
# 2
09-19-2007
Try...
 Ygor View Public Profile for Ygor Find all posts by Ygor
# 3
09-20-2007
As i told for C the problem comes

It should be max for the both..

That is
For C to complete it should have done B2 and B3

so C is max(B2,B3)+1

C=max(2,3)+1=4

but
Quote:
\$ awk '{print \$0, a[\$1]=1+a[\$2]}' file1
A NULL 1
B1 A 2
B2 A 3
B3 B1 3
C B3 4
C B2 3
this give both 3 and 4 but it should be max of it..

I can give u one more input file

A 0
B1 A
B2 A
B3 B1
C B3
C B2
D C
E C
F D
F E
I E

This is extention of previous

when i run the awk i get

A 0 1
B1 A 2
B2 A 2
B3 B1 3
C B3 4
C B2 3---- as it 3 here next one takes as 4 but it shoul be at level 5 ..
D C 4
E C 4
F D 5
F E 5
I E 5
 pbsrinivas View Public Profile for pbsrinivas Find all posts by pbsrinivas
# 4
09-20-2007
 Perderabo View Public Profile for Perderabo Find all posts by Perderabo
# 5
09-21-2007
Hi...

Thanks a lot for all the idea's

Its almost done... but .....

I am doing this to generate the level Numbers for Jobs to run in the unix server.. The input we have is the job name and it Predecessor Job Name

Small change required..

Have a look at the picture i have inserted..

If the Input is like this

A 0
B 0
C 0
D 0
E A
E B
E C
F E
G E
H E
I G
Z H
Z D

its perfect and works great..

But the same input and change in order..

A 0
B 0
C 0
D 0
E A
E B
E C
Z H
Z D

F E
G E
H E
I G

currupts the output.. gets me

A 0 1
B 0 1
C 0 1
D 0 1
E A 2
E B 2
E C 2
Z H 2
Z D 2
F E 3
G E 3
H E 3
I G 4

Just for the Pictorial view see the file i uploaded...
we have almost 1200 Jobs and it very tedious todo it..

Expected Out put
A 0 1
B 0 1
C 0 1
D 0 1
E A 2
E B 2
E C 2
Z H 4
Z D 4
F E 3
G E 3
H E 3
I G 4

We also have a file where it shows the Job and its Successor..

IF it could be of any use...

It like this

A E
B E
C E
D Z
E F
E G
E H
G I
H Z
I NULL
Z NULL
 pbsrinivas View Public Profile for pbsrinivas Find all posts by pbsrinivas
# 6
09-21-2007
This will never work unless you sort the input so that each job comes after all of its predecessors. The data pairs you have represent a directed graph. Provided that that the directed graph is acyclic, such a sort should be possible and this is called a topological sort. Lucky for you, Unix has a program called tsort to do this. Try:
But bear in mind that with a complex directed graph there will probably be several different ways to assign your level numbers. This will find one of them.
 Perderabo View Public Profile for Perderabo Find all posts by Perderabo
# 7
09-22-2007
Thanks a lot for the inputs..

Its working great.. but a small problem..

if we change the name of NODE "E" by P is does some thing unexpected..

like

just the same in put but change E as P

A 0
B 0
C 0
D 0
P A
P B
P C
Z H
Z D
F P
G P
H P
I G

the ouput i get.. (---- I have chaged ur script as \$3 instead of \$2....

sort \$1 > temp1
tsort temp1 | sed '\$d' | nl | sort -nr | cut -f2 | nl | awk '{print \$2, \$1}' | sort | join temp1 - | sort -k 3n | awk '{print \$1,\$3}' |\
awk '{r[NR]=\$0 ; k[NR]=\$1 ; if(v[\$1]<1+v[\$2]) v[\$1]=1+v[\$2] } END { for (n=1; n<=NR; n++) print r[n] , v[k[n]]}'
exit 0

A 0 1
B 0 1
C 0 1
D 0 1
F P 1
G P 1
H P 1
I G 2
P A 2
P B 2
P C 2
Z D 2
Z H 2

when E as E it great... no issues...

A 0 1
B 0 1
C 0 1
D 0 1
E A 2
E B 2
E C 2
F E 3
G E 3
H E 3
I G 4
Z D 4
Z H 4

by that i saw the tsort is fine..
but when the name of the jobs are in aphabetical order it has no problem

till this both produce same output

sort \$1 > temp1
tsort temp1 | sed '\$d' | nl | sort -nr | cut -f2 | nl | awk '{print \$2, \$1}'

but after that the sort |join temp1 - scatter the feilds..

Last edited by pbsrinivas; 09-22-2007 at 02:52 AM.. Reason: wrong anylisis... tsort is fine..... more analysis
 pbsrinivas View Public Profile for pbsrinivas Find all posts by pbsrinivas

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