File Accessed Alarm ??


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# 1  
Error File Accessed Alarm ??

Hey,

I want to ask a simple Question....

How would I be able to come to know that files/directoires in a Parent directory has been accessed (means contents of the file has been just viewed) by the user(s) in a group ? and mail the name(s) of those files/directories which has been accessed recently in past 1 or 2 minutes with the name of the user who viewed the files/direcotries.

How will I write script for this ??

Please answer this QUESTION asap as I am after this problem for past 15 days and I did't get any perfect answer.

Please Help !!Smilie
Thanks !!
# 2  
Try This one

Hey Varun,
Hope you guys are doing Gr8 !! Smilie
Once again I dun have any *NIX box with me. So why Just giving one logic by which you will get your answer.
-------------------------------------------------------------
#!/bin/bash

## List all the files which one accessed since last 1 min #####
for file_dir in `find <parent-dir> -atime -1`

do

### Find out the PID for that files which one been accessed
pid=`fuser -f $file_dir`

### Find out the owner/user name for that Process
### Replace the $access_user_filed with the filed no from the ps -ef
### command
user=`ps -ef | grep $pid | awk { print $access_user_filed }`
echo " $file_dir access by the $user " >> File_Access_List "
mail -s " File Access List " user@yourdomain.com < File_Access_List
done
# 3  
CPU & Memory

Quote:
Originally Posted by SanjayLinux
Hey Varun,
Hope you guys are doing Gr8 !! Smilie
Once again I dun have any *NIX box with me. So why Just giving one logic by which you will get your answer.
-------------------------------------------------------------
#!/bin/bash

## List all the files which one accessed since last 1 min #####
for file_dir in `find <parent-dir> -atime -1`

do

### Find out the PID for that files which one been accessed
pid=`fuser -f $file_dir`

### Find out the owner/user name for that Process
### Replace the $access_user_filed with the filed no from the ps -ef
### command
user=`ps -ef | grep $pid | awk { print $access_user_filed }`
echo " $file_dir access by the $user " >> File_Access_List "
mail -s " File Access List " user@yourdomain.com < File_Access_List
done
Hey,

Thanks buddy...I'll come back to you with the results of your post.
It looks fine !! Smilie
# 4  
Quote:
Originally Posted by SanjayLinux
Hey Varun,
Hope you guys are doing Gr8 !! Smilie
Once again I dun have any *NIX box with me. So why Just giving one logic by which you will get your answer.
-------------------------------------------------------------
#!/bin/bash

## List all the files which one accessed since last 1 min #####
for file_dir in `find <parent-dir> -atime -1`

do

### Find out the PID for that files which one been accessed
pid=`fuser -f $file_dir`

### Find out the owner/user name for that Process
### Replace the $access_user_filed with the filed no from the ps -ef
### command
user=`ps -ef | grep $pid | awk { print $access_user_filed }`
echo " $file_dir access by the $user " >> File_Access_List "
mail -s " File Access List " user@yourdomain.com < File_Access_List
done
Hey,
please clarify my doubt..
What is $access_user_filed , used in the following command ?user=`ps -ef | grep $pid | awk { print $access_user_filed }`

In ps -ef we have following columns..
UID PID PPID C STIME TTY TIME CMD
Are you talking about UID or anything else ??
# 5  
Sorry It is my typo.

$access_user_filed is actuly the UID(user id ) Filed no from the out put of ps -ef command

~~Thanks~~~
# 6  
Error

Quote:
Originally Posted by SanjayLinux
Sorry It is my typo.

$access_user_filed is actuly the UID(user id ) Filed no from the out put of ps -ef command

~~Thanks~~~
NO probs, I got that !!
Thnks !!Smilie
# 7  
Question

Quote:
Originally Posted by varungupta
Hey,
please clarify my doubt..
What is $access_user_filed , used in the following command ?user=`ps -ef | grep $pid | awk { print $access_user_filed }`

In ps -ef we have following columns..
UID PID PPID C STIME TTY TIME CMD
Are you talking about UID or anything else ??
Hey ,

When I run the script it gives me following error :

AccessLogMonitor_script[11]: 0403-057 Syntax error at line 23 : `"' is not matched.
And my script is, as per your suggestions :
---------------------------------------------------------------------
#SCRIPT TO CHECK WHO HAS ACCESSED THE LOG/FILE IN PAST 'N' MINUTES, AND MAIL ACCORDINGLY.

MYPATH="/clocal/mqbrkrs/user/mqsiadm/sanjay/"
MAIL_RECIPIENTS="abc@xyz.com"
Subject="File accessed in last few minutes are ::"
>tempmail.txt
>tempfind.txt

## List all the files which one accessed since last 1 min #####

for file_dir in `find $MYPATH -amin -1`
do
### Find out the PID for that files which one been accessed
pid = `fuser -f $file_dir`

### Find out the owner/user name for that Process
### Replace the $access_user_filed with the filed no from the ps -ef
### command
user = `ps -ef | grep $pid | awk { print $1 }`
echo " $file_dir access by the $user " >> tempmail.txt "
done

cat tempmail.txt | mailx -s "$Subject" "$MAIL_RECIPIENTS"
---------------------------------------------------------------------
Smilie
Suggest me !!
Thanks !!

Last edited by varungupta; 09-27-2007 at 09:05 AM..
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