Shell Programming and Scripting

Hi,

I currently have a script that takes a list of names and compares it with another list and appends non-duplicate names. I want to modify my script such that it will look at a list of names and for every name preceded by the tag "<delete>" (without the quotes) it checks the other list for that name and will remove it and with whatever else, it will perform the regular functionality of the script like before. So here's an example:

List1:
Jim
Bob
Ed
Hank

List2:
Greg
<delete>Hank
Dave

Result of List1 after the script run:
Jim
Bob
Ed
Greg
Dave

Can anyone help here? Thanks!

HI
I Hope this script works




#!/usr/bin/ksh



while read line
do
while read value
do
grep "<delete>" |pattern=`cut -d">" -f2`
if [ $pattern == $line ]
then
sed /$pattern/d file1
sed /$pattern/d file2 |sed '/^ *$/d'
fi
done <file2
done <file1

Try this

Code:

sed -n '/^\<delete\>/d' filename

Thanks! I'm assuming file1 and file2 are equivalent to my List1 and List2 right? So I tried running this and it gave me:

./other.sh[10]: [: argument expected
./other.sh[10]: [: argument expected
./other.sh[10]: [: argument expected
./other.sh[10]: [: argument expected
./other.sh[10]: [: argument expected
./other.sh[10]: [: argument expected
Jim
Bob
Ed
Greg
Dave
./other.sh[10]: [: argument expected
./other.sh[10]: [: argument expected


It seemed to have compiled the list right but I'm not sure of the errors. I ran the script pretty much like "./script.sh" Not sure if I was supposed to pass anything into it. Could the new list be stored in some file?

ok nm, I wrote up a similar script that did it for me. Thanks for the help anyways everyone!

Hi
the script is fine.

just change the if loop used to
if [ "$pattern" = "$line" ]

Also the script is hard coded.
If you dont have any delete tag in file2, it wud display nothing.
on other hand if you have 2 delete tags it will display the results twice...
if its ok for u ... fine...
or else we ll go for a better solution...

Happy scripting!!

Try this:

Code:

for var in $(cat list2); do

echo $var | grep "^<delete>" > /dev/null
if [[ $? -eq 0 ]]; then
Name=$(echo "$var" | cut -d">" -f2 )
echo $Name
grep -i "$Name" list1 >/dev/null
if [[ $? -eq 1 ]]; then
echo $var
fi

fi
done