Shell Programming and Scripting

Collegues
I am dealing with raw text files which is extracted from web pages.
I have to find sentances which contains more than 99 words and have to put a "." after the 99th or 98 th word .
Is there any possiblity to it in sed or awk
With regards
Jaganadh.H

Jaganadh,
Please, give us a sample of your file.

A first approach:

Code:

awk '
   BEGIN { RS = ORS = "." }
   { for (f=99; f<NF; f=f+99) $f=$f ORS ;print $0 }
' inputfile

The following is example sentance.
How ever the sentance may not be a meaning ful one.
The Six Ritus The six ritus and their properties can be summarized in the following table Kaal Ritu Maas Properties of the season Aadaan Solastice Sishira Magha and Phalguna January to mid march Cold and dewy season Vasanta Chaitra and Baisakh March to mid May Spring season Grishma Jyeshtha and Aashadha May to mid July Summer season Visarga Solastice Varsha Shravan and Bhadrapada July to mid September Rainy season Sharat Aashvin and Kartika September to mid November Autumn season Hemant Margshirsha and Pausha November to mid January Winter season Seasons and Tastes The following table summarizes the tastes which are more powerful and hence can be included in the diet in each of the six seasons .

Collegues
Thanks a lot for providing an effective solution for my querry.
I am using the charniak parser for some research. It does not take sentance longer than 100 words. Just I want to over ride the problem by a script. The script is working fine.

Jaganadh.G
Linguist

Code:

awk -F" " '{ $98 = $98" ."; print }' filename