Shell Programming and Scripting

Greetings,

I am trying to write script, (preferably in sh) that will use a proprietary program to print the resolution and name of files in the current working directory in a vertical format.

I think this script will require 3 commands with variables and a pipe to the prop program, but am not sure.

This is what I have so far-

ls|while read line do resolution=`itstat|grep Resolution|cut -f2 -d:` echo "$line: $resolution"

i tried and got a syntax line error.

If someone could help me figure this out, I would be grateful.

cheers
roc

Code:

ls|while read line; do resolution=`itstat|grep Resolution|cut -f2 -d:` ; echo "$line: $resolution"; done

Thank you very much!

Thanks again!

How would I use this script to send a list of the files with a given resolution to a text file?

Code:

ls|while read line; do resolution=`itstat|grep Resolution|cut -f2 -d:` ; echo "$line: $resolution" > resln_file  ; done

what shell is this script for?

for the print variable :

> resln_file

how does this take only files with a certain resolution and print them to a directory.

You can use in ksh and bash

Code:

ls|while read line; do resolution=`itstat|grep Resolution|cut -f2 -d:` ; if [ $resolution -eq 23 ]; then echo "$line: $resolution" > resln_file ; fi  ; done