Shell Programming and Scripting

Hello, I have a file with several lines

for example;

I need to extract a line radiusAuthServTotalAccessRequests.0 = 0
and I don't have line #s in the file.

I need to write a script to extract the above line, put a date beside it and parse this line out to another directory / file.

How can I do this ?

You feedback would be greatly appreciated

Thank you so much to those who already replied and those who will reply.

You can do something like that:

Code:

read line < infile # read first line
echo "$(date +'%d/%m/%Y') ${line}" > outfile

With your file example, the outfile is :

Code:

30/05/2007 A

Jean-Pierre.

Xeniya,
See if is this what you want.
'input_file' is the file with your lines (A, B, C, etc.)

Code:

while read mEachLine
do
  mNewLine=${mEachLine}"<your_date_here>"
  ### use 'mNewLine' as you wish ###
done < input_file

Code:

awk '/radiusAuthServTotalAccessRequests/{"date +%Y%m%d"|getline d 
                                         print d" "$0> "outfile"}' "file"

Xeniya,
I can see that you changed your original request.
Instead you should issue another post.
It is not fair to the people that offer solutions to change your original
specifications after the solutions have been given.

Oh, i am so sorry, I am new to this Forum and don't know all the rules yet. I thought editing the original reply was the thing to do but I guess not. I didn't mean to cause trouble, sorry.