Shell Programming and Scripting

Try that:

Code:

awk '/^\[/,/^]/ { if ($3 == "X") $1=++line } 1' filename

Jean-Pierre.

Hello Anbu23!

The code you gave worked fine.

I tried to use similar nawk command to the file below but nothing happened.

nawk -v no=1 ' /M_I : \[/,/\]/ { if ( $1 ~ "^[0-9]+ " && $7 == "HI" ) { sub("^[0-9]+ ",no" ");no++}}; 1 ' filename

Contents of "filename":

D : [
# ===========



]


S : [
# ============

Nb_S_I : 5
S_I : [

# R_L "S_D"
56 "1-2x"
48 "1-2x"
40 "1-2x"
32 "1-2x"
24 "1-2x"

]

]


M_I : [
# ===========


# M_I B_T S_Nb C_Nb L_N P_Nb O M_I A_F D_F
4 X 9 1 2 4 HI 1 F F
5 F 2 1 4 0 HI 1 F F
6 F 4 1 6 0 HI 1 F F
10 L 1 1 8 4 HI 1 F F
]


The output should be as follows:

D : [
# ===========



]


S : [
# ============

Nb_S_I : 5
S_I : [

# R_L "S_D"
56 "1-2x"
48 "1-2x"
40 "1-2x"
32 "1-2x"
24 "1-2x"

]

]


M_I : [
# ===========


# M_I B_T S_Nb C_Nb L_N P_Nb O M_I A_F D_F
1 X 9 1 2 4 HI 1 F F
2 F 2 1 4 0 HI 1 F F
3 F 4 1 6 0 HI 1 F F
4 L 1 1 8 4 HI 1 F F

]

The field $1 can't contain a space that is a separator.
Change your test :

Code:

nawk -v no=1 ' /M_I : \[/,/\]/ { if ( $0 ~ "^[0-9]+ " && $7 == "HI" ) { sub("^[0-9]+ ",no" ");no++}}; 1 ' filename

The nawk program can be simplified:

Code:

nawk '/M_I : \[/,/\]/ { if ( $0 ~ /^[0-9]\+ / && $7 == "HI" ) $1 = ++no }; 1 ' filename

Jean-Pierre.

I have attached a sample file about the actual format of the lines I want its line numbers changed.

I used the following script to change the line numbers:

#! /bin/ksh

cd $HOME/lib
nawk -v no=1 ' /Marker_Item : \[/,/\]/ { if ( $5 == "HIGH" ) {sub($1,no);++no}}; 1 ' filename

As you noticed at the results, the alignment for lines 7, 8 and 9 has changed. Any ideas on how to realign it?

Thanks!

if you have Python, here's an alternative;

Code:

flag = False
num=1 # renaming counter
for line in open("file"):
    line = line.strip()
    if line.startswith("M_I : ["): flag = True
    if flag:        
        l = line.split()    
        try:
            if l[0].isdigit():
                l[0]=str(num)
                num+=1                 
        except:pass
        print " ".join(l)
    else:print line
    if line.startswith("]"):
        flag = False

output:

Code:

# ./test.py

D : [
# ===========



]


S : [
# ============

Nb_S_I : 5
S_I : [

# R_L "S_D"
56 "1-2x"
48 "1-2x"
40 "1-2x"
32 "1-2x"
24 "1-2x"

]

]


M_I : [
# ===========


# M_I B_T S_Nb C_Nb L_N P_Nb O M_I A_F D_F
1 X 9 1 2 4 HI 1 F F
2 F 2 1 4 0 HI 1 F F
3 F 4 1 6 0 HI 1 F F
4 L 1 1 8 4 HI 1 F F
]

I'm sorry ghostdog74 'coz I just use ksh shell.

Thanks for your help anyway.

Code:

nawk ' /Marker_Item : \[/,/\]/ { 
	if ( $5 == "HIGH" ) {
		str=$0;
		sub($1".*",$1,str);
		sub(" *"$1,sprintf("%*d",length(str),++no))
	}
}; 1 ' filename