Shell Programming and Scripting

Hello again;

I have a directories and subdirectories in my current directory and i wanna to find the directories( and subdirectories ) which are larger than what user enters as first parameter.

find . -type d -size +"$1"c -print > directories.dat

I used this command and i am not sure it is working properly.
Because i entered the
./myprog.sh 300
and it found empty directory.

Or i entered the
./myprog.sh 500000
and it found nothing however in the current directory i have directories which are larger than 500000 bytes

i wonder this command are working for directory search or not working

Thanks for your replies..

Code:

>cat b2.zsh
echo "find . -type d -maxdepth 1 -size +$1k -print" | zsh

Code:

>./b2.zsh 3

Hmm..it works fine for me..that's right command..

if this command does not success, why?
find . -type d -size +"$1"c -print > directories.dat

i cannot understand your code in addition i wrote this in my program and i does not work too.
İ wanna know that why this code is not working properly and where am i wrong?And how can i fix it?

find . -type d -size +"$1"c -print > directories.dat

İ have many directories and subdirectories in my current directory and i wanna list them (which are bigger) in directories.dat file.
That is all

just execute manually..not through script and give a try..

find . -type d -size +<size>c -ls

You folks may not be on the same page here....

A directory entry is a name and an inode number. A directory is a file that contains a collection of these entries. If I create a new directory, it will be rather small. If I cd into it and create 5 100GB files, my directory continues to be small... after all it only has 7 entries at this point.

Please clarify if you are discussing the size of a directory or the collective total of disk space used by a directory and all files and subdirectories contained within it.