Shell Programming and Scripting

I could use some more help on the same topic. Now I need to use sed to delete the portion of the line in parenthesis if the line begins with CHAR. Thanks everyone.

This is the command I'm playing with:

Code:

sed -e '/CHAR/!s/([A-Z0-9]*//g'

BASE DESCRIPTION (BSEDS)
This would become this
BASE DESCRIPTION

This would not change
CHAR BASE DESCRIPTION (BSEDS)

Turbulence,

If you want to delete the portion of the line in parenthesis if the line begins with CHAR, you can try this:

Code:

echo "CHAR BASE DESCRIPTION (BSEDS)" | sed 's/^(CHAR.*\)(.*)/\1/'

Above will omit line if there is "_" anywhere in the line, it doesn't look specifically for the '_;' at the end of line, e.g.

Code:

(string \\;\) cba_se
(string \\;\) bse;
(string \\;\) cflavor_;
(string \\;\) flv;

Output:

Code:

(string \\;\) cbse;
(string \\;\) cflv;

Regards,
Tayyab

Thank you for your help but your command is giving me an error.

Code:

echo "CHAR BASE DESCRIPTION (BSEDS)" | sed 's/^\(CHAR.*\)(.*)/\1/'
sed: -e expression #1, char 21: Unmatched ) or \)

I tried adding slashes and parens in several places but it still wouldn't work.

Edit: I got it to work but it's doing the opposite of what I need. I need it to *not* delete from lines starting with CHAR.

CHAR BASE DESCRIPTION (BSEDS)
this would stay the same.

BASE DESCRIPTION (BSEDS)
would become
BASE DESCRIPTION

I found the solution. Here it is in case anyone wants to use it in the future.

Code:

sed -e '/CHAR/ !s/^\(.*\) (.*)/\1/'

Hi, I am trying do the same as above but I want to delete all lines that do not start with a '-' negative sign...so i tried the above command by replacing CHAR with - ....but did not work...any other suggestions?

Code:

sed '/^[^-]/d'