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awk conditional statement

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# 1  
Old 08-08-2006
awk conditional statement
how can i use awk or sed to do a conditional statement, so that
HH:MM
if MM not great than 30 , then MM=00
else MM=30

ie:
10:34 will display 10:30
10:29 will display 10:00

a=$(echo 10:34 | awk ......)


Thanks in advance
# 2  
Old 08-08-2006
Use awk. You can't use sed (atleast to my knowledge).
Code:
echo "10:34" | nawk -F: '{if($2<30) printf("%d:00",$1)
else printf("%d:30",$1)}'

# 3  
Old 08-08-2006
echo HH:MM | awk -F: '{if ($2>30) { New_mm=30 } else {New_mm=00}; print $1":"New_mm}'

Have fun!!! Smilie
# 4  
Old 08-08-2006
thank !

but how can i make the output to be 00 instead of only contain one 0
# 5  
Old 08-08-2006
oh, thanks ! i got it...
# 6  
Old 08-08-2006
sorry
how if my input field is HH:MM:XX:YY:ZZ..... and i want to replace the MM with either 00 or 30 ?

thanks
# 7  
Old 08-08-2006
Hi friend,

I have written below 2 line of code,
1. create a file with of diffrent value that we will use for testing.
2. Cat that file and check for the second parameter if it is greater than 30 then it will print 30. else it will print 00. You can put any value in place of other parameter.

Code:
1.  for((i=0;i<60;i++)); do echo "HH:$i:XX:YY:ZZ" >> tmp.txt; done
2. cat tmp.txt | awk -F":" '{ if($2<30) printf("%s:00:%s:%s:%s\n",$1,$3,$4,$5);} { if($2>30) printf("%s:30:%s:%s:%s\n",$1,$3,$4,$5);} '

Smilie Smilie Smilie Smilie Smilie
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