A better way to compare text length percentage?


 
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# 1  
Old 04-23-2020
Try:
Code:
echo ${#text1} ${#text2} |  awk '{print (100/$1*$2) }'

Hope this helps
# 2  
Old 04-23-2020
Quote:
Originally Posted by sea
Try:
Code:
echo ${#text1} ${#text2} |  awk '{print (100/$1*$2) }'

Hope this helps
Thank you. This is cool in that it seems to solve the 'division by zero' issue. Smilie


Yet this works in only one way.


For example:
Code:
$ text1='ab'; text2='abcd'; s1=${#text1}; s2=${#text2}
$ echo ${#text1} ${#text2} |  awk '{print (100/$1*$2) }'
200

but
Code:
$ text1='abcd'; text2='ab'; s1=${#text1}; s2=${#text2}
$ echo ${#text1} ${#text2} |  awk '{print (100/$1*$2) }'
 50

I need both answers to say 200[%]. The text should be able to be swapped and still say the same value. The order does not matter to me, just how much bigger the bigger value is.


There must be some type of inverse equation or function/app that could be used. Smilie
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