Getting number of argument passed to a shell script
Hi Experts,
I have been trying to work on a simple shell script that will just add the two argument passed to it. Here is what i tried :
Below is the output which isn't correct :-
Any idea what am I doing wrong?
Yes, and as you have already received the solution i wil concentrate on explaining the reason:
When you invoke a process with some arguments these arguments become part of the "process environment". Inside a script you can then use special variables ("$@", "$*", "$1", "$2", ...) to pull these arguments out of the environment or get ("$#") the number of parameters passed.
But every time you invoke a shell function inside a script this function gets its own environment of sorts and all the special variables "$1", "$2", etc. and "$#" describe what is passed as argument to the function instead of what is passed to the main script. Look at the following sample script:
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----------
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