10 More Discussions You Might Find Interesting
1. UNIX for Beginners Questions & Answers
My sample file is variable length, with out any field delimiters. It has min of 18 chars length and the 'CRLF' is potentially between 12-14 chars. How do I replace this with a space? I still want to keep end of record, but just want to remove these new lines chars in the middle of the data.
... (7 Replies)
Discussion started by: chandrath
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2. Shell Programming and Scripting
here is what i want to achieve... consider a file contains below contents. the file size is large about 60mb
cat dump.sql
INSERT INTO `table1` (`id`, `action`, `date`, `descrip`, `lastModified`) VALUES (1,'Change','2011-05-05 00:00:00','Account Updated','2012-02-10... (10 Replies)
Discussion started by: vivek d r
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3. Shell Programming and Scripting
Hello All,
I working on ksh. I am using fixed length file. My file is like:
========
IXTTIV110827 NANTH AM IKSHIT
ABCDEF 0617 IJAY NAND EENIG
ZXYWVU 0912 AP OOK OONG
PQRSTU100923 NASA DISH TTY
ASDFG 0223 GHU UMA LAM
QWERT 0111 ATHE SH THEW
=======
From 7th to 12 is a date... (4 Replies)
Discussion started by: AnanthaDikshit
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4. Shell Programming and Scripting
Suppose i have a file which contains thousands of records. e.g adjgmptjadmwpgjmwmd i need to replace the string from 3rd to 8th position using awk script in entire file. And also the positions will be passed as parameter. (3 Replies)
Discussion started by: laknar
3 Replies
5. Shell Programming and Scripting
Hello,
I really would appreciate some help with a bash script for some string manipulation on an SQL dump:
I'd like to be able to rename "sites/WHATEVER/files" to "sites/SOMETHINGELSE/files" within the sql dump.
This is quite easy with sed:
sed -e... (1 Reply)
Discussion started by: otrotipo
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6. Shell Programming and Scripting
I have a customer who logged some cc and bank account numbers in their apache logs. I got the cc numbers x'd out with
sed -e 's/args=\{16\}/args=XXXXXXXXXXXXXXXX/g' -e 's/cardnum=\{16\}/cardnum=XXXXXXXXXXXXXXXX/g'but that wasn't too difficult due to the value being 16 digits.
The bank account... (7 Replies)
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7. UNIX for Dummies Questions & Answers
HI
In my script, i am reading the input from the user and want to find the length of the string.
The input may contain leading spaces. Right now, when leading spaces are there, they are not counted.
Kindly help me
My script is like below. I am using the ksh.
#!/usr/bin/ksh
echo... (2 Replies)
Discussion started by: dayamatrix
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8. Shell Programming and Scripting
$ cat template
s.noName
$ sed "s/s.no/1/" template > out
$ sed "s/s.no/100/" template >>out
$ cat out
1Name
100Name
1 Name
100Name (7 Replies)
Discussion started by: McLan
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9. Shell Programming and Scripting
Hello All,
Plz help me with:
I have a csv file with data separated by ',' and optionally enclosed by "". I want to check each of these values to see if they exceed the specified string length, and if they do I want to cut just that value to the max length allowed and keep the csv format as it... (9 Replies)
Discussion started by: ozzy80
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10. Shell Programming and Scripting
Hi guys, I hope you can help me with my problem.
I have a text file that contains lines like this:
78 ANGELO -809.05
79 ANGELO2 -5,000.06
I need to find all occurences of amounts that are negative and replace them with x's
78 ANGELO xxxxxxx
79... (4 Replies)
Discussion started by: amangeles
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bup-margin(1) General Commands Manual bup-margin(1)
NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS
--predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO
bup-midx(1), bup-save(1)
BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown- bup-margin(1)