10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
Hi,
Extremely new to Perl scripting, but need a quick fix without using TEXT::CSV
I need to read in a file, pass any delimiter as an argument, and convert it to bar delimited on the output. In addition, enclose fields within double quotes in case of any embedded delimiters.
Any help would... (2 Replies)
Discussion started by: JPB1977
2 Replies
2. UNIX for Dummies Questions & Answers
Hi,
I have a input
/dev/cm/test1.txt
/qa/tm/hmkr/cc/test2.txt
and I need an out like below
foldername, filename
/dev/cm/,test1.txt
/qa/tm/hmkr/cc/,test2.txt
I tried with awk $NF, but I'm getting the filenames and not folder names. Please let me know how to achive the above... (5 Replies)
Discussion started by: somu_june
5 Replies
3. Shell Programming and Scripting
Hi,
I have a No Delimiter variable length text file with following schema -
Column Name Data length
Firstname 5
Lastname 5
age 3
phoneno1 10
phoneno2 10
phoneno3 10
sample data - ... (16 Replies)
Discussion started by: Gaurav Martha
16 Replies
4. Shell Programming and Scripting
Hi there,
I am with this one column input text file to change layout, please help. Thanks. I have awk, sed.
$ cat input
Median
1.0
2.3
3.0
Median
35.0
26.3
45.7
10.1
63.1
Median
1.2
2.3 (8 Replies)
Discussion started by: cwzkevin
8 Replies
5. UNIX for Advanced & Expert Users
Hi All,
I woul like to know with out opening a file in unix ,how we can find out what is the delemeter in that file...
Thanks..
edit by bakunin: changed thread title to "delimiter" so it can be found. (4 Replies)
Discussion started by: raju4u
4 Replies
6. Shell Programming and Scripting
Hello,
I am trying to find the record count in a specific folder,
Here is the part of the code
===========================
STARTDATE=`date +"%y%m%d%H%M"`
for i in `ls *.DAT`
do
wc -l $i >> /XYZ/SrcFiles/"Record_counts"$STARTDATE.csv
... (2 Replies)
Discussion started by: Shanks
2 Replies
7. Shell Programming and Scripting
#/bin/sh
sysdate=`date +"%m/%d/%Y"`
systime=`date +%r`
ps_per=`lsps -s | nawk '{print $2+0}'|tail -1`
ps_tot=`lsps -s | nawk '{print $1+0}'|tail -1`
lcpu=`vmstat | nawk -F= '/lcpu/ {print $2+0}'`
mem_tot=`vmstat | nawk -F= '/mem=/ {print $3+0}'`
avm=`vmstat|awk '{print... (7 Replies)
Discussion started by: Daniel Gate
7 Replies
8. UNIX for Dummies Questions & Answers
Hi
I have a file in which delimiter is ';'
However if the delimiter is within "" it is a part of the string and not delimiter.
How to get the fields ? I want to replace the delimiter ';' to '|'.
The file contains data like this :
11111; “2222 2222”; “3333; 3333”; “4444 ""44444”
The file... (2 Replies)
Discussion started by: dashing201
2 Replies
9. Shell Programming and Scripting
hi, pls someone tell me how to extract delimiters from any file and pass it to a unix script.since, im a beginner in unix i find it little bit difficult.how to use awk to do this? (9 Replies)
Discussion started by: sureshmit
9 Replies
10. Shell Programming and Scripting
Hi,
I just wandering how to split a record which has more than one delimiter,
i have a file which contains pattern as group separtor and ~ as field separtor, Ultimately I need consider even the groups as a field, So i need to make this multi-delimited file into ~ delimited file.
My record... (4 Replies)
Discussion started by: braindrain
4 Replies