Shell Programming and Scripting

You might note that in post #2 in this thread I didn't ask about the shell being used (partly because it doesn't matter here and partly because bash had already been specified).

I did ask about the OS, and it does matter here if an awk solution is appropriate (as in the suggestion I would provide if ChicagoBlues showed us that any effort had been put into this problem) since on Solaris systems awk would need to be changed to /usr/xpg4/bin/awk or nawk.

Also, the shell does matter more on Solaris systems than on many other systems since /bin/sh there is a pure Bourne shell lacking several standard shell parameter expansions, arithmetic expansions, and the $(command) form of command substitution.

A simple grep against the whole file worked for me (within the loop). Initially, I wasn't thinking of wrapping it in a loop. If you have a more efficient solution, then please share.

Code:

  for platform in $(cat $DATA_OUT/tmp_ALLL_Platforms.txt); do
    warning=`grep $platform $DATA_OUT/ALL_warnings.txt`

    ... rest of the code

    done

For the original problem you posed in post #1 in this thread, the following works perfectly:

Code:

/usr/xpg4/bin/awk -F'[";]' '
FNR == NR {
	t[$2] = $0
	next
}
{	print t[$2]
}' tmp.new tmp.orig

But, since the data you showed us in post #1 would not find any matches with the code you showed us in post #9, I have to assume that the data you showed us is not representative of your actual data.

A for loop is not good when you need to read from a file. You could eliminate an extra call to the cat command by using a while loop.

Code:

while read platform; do
    do something here with $platform
done < "${DATA_OUT}"/tmp_ALLL_Platforms.txt

Concerning your request.

Code:

tr -d \" < tmp.orig | grep -Ff - tmp.new
"TEST1;921"
"TEST2;34"
"TEST5;98"
"TEST6;1"