Shell Programming and Scripting

HUm... this is not working as I wish

But I wrote this code like this can you show me the right way ??


If a file like test.in

Case Modify 10001 20002 30003 40004|Report Create 3417176211|Case Modify 10002 20002 30003 40005|CDxAcct=8201062400|CDxAcct=7294483553|


#!/bin/ksh
#remove.ksh
REMOVE=$1


cat test.in |
awk -F"\n" -v remove=$1 '{
input=$1;

remove_start=index(input,remove);
if (remove_start == 0) {
output = input;
} else {
if (remove_start == 1) {

output = substr(input,index(input,"|")+1);
} else {

output1 = substr(input,1,remove_start - 1);
output2 = substr(input,remove_start);
output = output1 substr(output2,index(output2,"|")+1);
}
}
printf "%s\n",output;
}'


Then if I run script
[b]
$remove.ksh "Case"
Report Create 3417176211|Case Modify 10002 20002 30003 40005|CDxAcct=8201062400|CDxAcct=7294483553|
It remove the first field ... it should not remove anything..

If I type
$remove.ksh "Case Modify 10002" then the answer should be
Case Modify 10001 20002 30003 40004|Report Create 3417176211|CDxAcct=8201062400|CDxAcct=7294483553|


and if do
$remove.ksh "Case Modify 10001" then the answer should be

Report Create 3417176211|Case Modify 10002 20002 30003 40005|CDxAcct=8201062400|CDxAcct=7294483553|


Please show me what I should do . Thanks

Code:

#!/bin/ksh

REMOVE=$1

cat test.in | tr '\|' '\n' | grep -v ^$ | grep -v "$REMOVE" | tr '\n' '\|'
echo

exit 0