Shell Programming and Scripting

I need to write a shell script which checks the CPU utilization is above 90% for a particular process.

So far I have done this

prstat 0 1 | grep weblogic | awk '{print $9}'

This give an output like this

0.1%
0.0%
0.0%
0.0%
0.0%


Now I need to assign this to an array and check if the value exceeds 90%.
If so then I should print an alert message in the script.

Please help me to do the same.

Thanks
Joe

Try running this:

Code:

prstat 0 1 | grep weblogic | awk '{print $9}' | while read line;
do
if [ ${line%%\%} -gt 90 ]; then
        # send alert here!
fi
done

Note, this will not work if the % value is something like 90.7%. It has to be 91 or more.

this one would do,

assuming single precision,

Code:

prstat 0 1 | grep weblogic | awk '{print $9}' | sed 's/%//' | while line do
 if [ `echo $line \* 10 | bc` -gt 900 ]
 then
 echo "$line greater than 90"
 else
 echo "$line not greater than 90"
 fi
 done

Nice one. Instead of assuming single precision, why not use 100 as the multiplier and check against 9000?

ya, ...

i just made a quick glance at the output of the command and
hence restricted it to single precision