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1. Shell Programming and Scripting
im using the following code to grab data, but after the data in the range im specifying has been grabbed, i want to count how many instances of a particular pattern is found?
awk 'BEGIN{count=0} /parmlib.*RSP/,/seqfiles.*SSD/ {print; count++ } /103 error in ata file/ END { print count }'... (3 Replies)
Discussion started by: SkySmart
3 Replies
2. Shell Programming and Scripting
Hi ,
I have an issue where I want to parse through the output from a file and I want to grab the nth occurrence of text in between two patterns preferably using awk or sed
! TICKET NBR : 1 !GSI : 102 ! 3100.2.112.1 11/06/2013 15:56:29 ! 3100.2.22.3 98 ! 3100.2.134.2... (8 Replies)
Discussion started by: OTNA
8 Replies
3. Shell Programming and Scripting
Hi Everyone, I have the below information from a log file:
LOAD SUMMARY
============
WRT_8036 Target: TGT_1_TAB (Instance Name: )
WRT_8039 Inserted rows - Requested: 3929 Applied: 0 Rejected: 3929 Affected: 0 Mutated from update: 3929
WRT_8041 Updated rows ... (7 Replies)
Discussion started by: galaxy_rocky
7 Replies
4. Shell Programming and Scripting
The following text is in testFile.txt:
one 5
two 10
three 15
four 20
five 25
six 10
seven 35
eight 10
nine 45
ten 50
I'd like to use sed to print the first occurance of search pattern /10/ in a given range. This command is to be run against large log files, so to optimize efficiency,... (9 Replies)
Discussion started by: uschaafm
9 Replies
5. Shell Programming and Scripting
Hello All
I have a file with this type of records:
=LDR 01157nas a22003011a 4500
=001 vtls000000013
=003 VRT
=005 20111020150800.0
=008 100128c19699999sp\a|||||\||||0\\\||spa|
=037 \\$a1327$i090$j090$k03
=039 ... (14 Replies)
Discussion started by: ldiaz2106
14 Replies
6. Shell Programming and Scripting
Hi,
Here is my piece of code used with sed in shell script:
sed -i '/<falsemodule-option>/ a\<LdapLogin>' myxmlfile
The problem that i am facing with the above is that in 'myxml' file i have mulitple instances of <falsemodule-option>
so when i execute the above sed command, it is appending... (10 Replies)
Discussion started by: sunrexstar
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7. UNIX for Dummies Questions & Answers
Alright, here's the deal. I'm running the following ruby script (output follows):
>> /Users/name/bin/acweather.rb -z 54321 -o /Users/name/bin -c
Clouds AND Sun 57/33 - Mostly sunny and cool
I want to just grab the "57/33" portion, but that's it. I don't want any other portion of the line. I... (5 Replies)
Discussion started by: compulsiveguile
5 Replies
8. Shell Programming and Scripting
hi
i have one file where i want to substitute only first instance of
swap
with swap1
i want to replcae only first instance of swap in my script
i know we can do this with awk. but i need to do this with sed only
i tried follwoing code
sed 's/swap/swap1' filename
but here all... (15 Replies)
Discussion started by: d_swapneel14
15 Replies
9. Shell Programming and Scripting
Hi, I've been trying to figure this one out and found a post about this on the forum here but the solution didn't seem to work for me. Basically what I have is a file that looks something like:
stuff
morestuff
0
otherthing
0
etc
I want to substitute for the 0 but what I want to... (9 Replies)
Discussion started by: eltinator
9 Replies
10. Shell Programming and Scripting
Hello,
I want to replace 2nd instance of "foo" in a file use sed.
Any suggestions? (2 Replies)
Discussion started by: katrvu
2 Replies
bup-margin(1) General Commands Manual bup-margin(1)
NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS
--predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO
bup-midx(1), bup-save(1)
BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown- bup-margin(1)