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Count and print the most repeating string in each line

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# 8  
Old 03-17-2015
Hi, in builtin bash ( bash 4 or higher) just for fun:
Code:
#!/bin/bash
unset XX
declare -A XX
while read A B
do
        [[ ${XX[$A]} =~ ${B}_[0-9]* ]] && { C=${B}_$((${BASH_REMATCH[@]//*_/}+1)) ; XX[$A]=${XX[$A]/${BASH_REMATCH[@]}/${C}} ; } || XX[$A]+="${B}_1 "
done <input1.txt

for i in ${!XX[@]}
do
        b=""
        a=0
        for j in ${XX[$i]}
        do
                [ ${j//*_/} -ge $a ] && { a=${j//*_/} ; [ ${j//*_/} -eq $a ] && b="$b ${j//_*/} $a" || b="${j//_*/} $a" ;}
        done
        echo $i $b
done

Regards.
Last edited by disedorgue; 03-17-2015 at 04:08 PM.. Reason: To notify bash version
# 9  
Old 03-17-2015
Quote:
Originally Posted by disedorgue
Hi, in builtin bash just for fun:
Code:
#!/bin/bash
unset XX
declare -A XX
while read A B
do
        [[ ${XX[$A]} =~ ${B}_[0-9]* ]] && { C=${B}_$((${BASH_REMATCH[@]//*_/}+1)) ; XX[$A]=${XX[$A]/${BASH_REMATCH[@]}/${C}} ; } || XX[$A]+="${B}_1 "
done <input1.txt

for i in ${!XX[@]}
do
        b=""
        a=0
        for j in ${XX[$i]}
        do
                [ ${j//*_/} -ge $a ] && { a=${j//*_/} ; [ ${j//*_/} -eq $a ] && b="$b ${j//_*/} $a" || b="${j//_*/} $a" ;}
        done
        echo $i $b
done

Regards.
When I try this with the following version of bash:
Code:
GNU bash, version 3.2.57(1)-release (x86_64-apple-darwin14)
Copyright (C) 2007 Free Software Foundation, Inc.

I get the output:
Code:
disedorgue: line 3: declare: -A: invalid option
declare: usage: declare [-afFirtx] [-p] [name[=value] ...]
0 BP1 3 BP3 4

If I change line 3 to:
Code:
declare -a XX

or comment out that line, I get the output:
Code:
0 BP1 3 BP3 4

Which version of bash is required to make this work?
# 10  
Old 03-17-2015
Bash 4 or higher:
Code:
$ bash -c 'declare -A XX'
bash: line 0: declare: -A: invalid option
declare: usage: declare [-afFirtx] [-p] [name[=value] ...]
$ bash4 -c 'declare -A XX'
$

This User Gave Thanks to Scrutinizer For This Post:
disedorgue
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