Shell Programming and Scripting

Hello,

I am new to shell scripting.

I have a input file: Few lines of the input file has the following.

/a0012/abcd12/abcd12
/a0003/xyzab1/lmno123
/a0006/pqrst1/abcde12

In my output file, I only need to get anything that is between the first and second '/' of each line: exampple:
a0012 a0003 a0006

Using grep I have got the above three lines from a huge input file. But not sure how to go forward with my problem.

Please help.

thanks
Hemang

use the following

awk -F '/' '{print $2}' f1.txt

where your data is in f1.txt

Gaurav

Gaurav,

Thanks..

But,
(1) The output is on different lines...
I want them all to show up on one line with 'space' as a seperator.

(2) I would appreciate if you could you also explain the syntax to me. I am kind of learning on own while working on it.

thanks again.

One more question:

How can i assign the output value to a variable?

I tried the below and did not work.
Not sure what syntax is required.
awk_var=awk -F '/' '{print $2}' file.input

Please help.
thanks

Instead of print use printf("%s ",$2).

What type of variable: shell's or awk's ?

Hi,
You had three quesions,

1) fidodido already replied for it, thanks fidodido for telling such a simple way of doing it

2)Go through man pages for awk you will understand it and may be go through sed and awk book from orelly or some other resources for awk using google

3)use the following

awk_var=`awk -F '/' '{print $2}' file.input`

if still some confusion post back to here

Gaurav

Thank you Fidodido and Gaurav.
It worked both ways.

Fidodido,
The variable I was trying to use was a shell variable.
It is working now. I had syntax issues.

thanks again..