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How to merge variable data from another file into specific place?

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# 1  
Old 01-13-2015
How to merge variable data from another file into specific place?
Hello,

I'm trying to create multiple commands using a variable input from another file but am not getting any successful results.

Basically, file1.txt contains multiple lines with single words:

Code:
<file1.txt>
yellow
blue
black
white

I want to create multiple echo commands with these words in the middle of the echo:

Code:
echo "This color is $file1.txt and will be ready ASAP"

Expected result:

Code:
echo "This color is yellow and will be ready ASAP"
echo "This color is blue and will be ready ASAP"
echo "This color is black and will be ready ASAP"
echo "This color is white and will be ready ASAP"

This is the best I got so far:

Code:
for i in $(cat file1.txt);do echo "$i";echo "This color is $i and will be ready ASAP"

output is:

yellow
This color is yellow and will be ready ASAP
blue
This color is blue and will be ready ASAP
black
This color is black and will be ready ASAP
white
This color is white and will be ready ASAP

Is there any other way that is more effective in doing this task without adding an extra word before the echo? This command seems to take a lot of CPU.

Thanks!
# 2  
Old 01-13-2015
Code:
 
 while read line; do echo "echo "\"This color is $line and will be ready ASAP"\""; done < file1.txt

with awk

Code:
awk '{print "echo ""\"This  color is "$0" and will be ready ASAP\""}' file1.txt

Last edited by senhia83; 01-13-2015 at 03:33 PM..
This User Gave Thanks to senhia83 For This Post:
demmel
# 3  
Old 01-13-2015
couple of more options:

Code:
sed 's/.*/echo "This color is & and will be ready ASAP"/' file1.txt
 printf 'echo "This color is %s and will be ready ASAP"\n' $(cat file1.txt)

This User Gave Thanks to Chubler_XL For This Post:
demmel
# 4  
Old 01-13-2015
printf is cool, let's put xargs on top!
Code:
 <file1.txt xargs printf 'echo "This color is %s and will be ready ASAP"\n'

Smilie
These 2 Users Gave Thanks to MadeInGermany For This Post:
Chubler_XL demmel
# 5  
Old 01-13-2015
Quote:
Originally Posted by senhia83
Code:
 
 while read line; do echo "echo "\"This color is $line and will be ready ASAP"\""; done < file1.txt

[..]
Two quotes too many, which would leave the variable unquoted.
Code:
while read line; do
  echo "echo \"This color is $line and will be ready ASAP\""
done < file1.txt

This User Gave Thanks to Scrutinizer For This Post:
demmel
# 6  
Old 01-13-2015
Quote:
Originally Posted by Scrutinizer
Two quotes too many, which would leave the variable unquoted.
Both gives me the same result though on cygwin !

Code:
$ while read line; do echo "echo "\"This color is $line and will be ready ASAP"\""; done < tmp
echo "This color is yellow and will be ready ASAP"
echo "This color is blue and will be ready ASAP"
echo "This color is black and will be ready ASAP"
echo "This color is white and will be ready ASAP"


$ while read line; do
>   echo "echo \"This color is $line and will be ready ASAP\""
> done < tmp
echo "This color is yellow and will be ready ASAP"
echo "This color is blue and will be ready ASAP"
echo "This color is black and will be ready ASAP"
echo "This color is white and will be ready ASAP"

This User Gave Thanks to senhia83 For This Post:
demmel
# 7  
Old 01-13-2015
With your extra quotes the $line is not inside quotes, giving some vulnerability.
For demonstration, add another line with a * to file1.txt
BTW, Chubler's $(cat file1.txt) is also vulnerable.
This User Gave Thanks to MadeInGermany For This Post:
demmel
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