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How to make working this regex in perl?

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# 8  
Old 12-02-2014
You want to break a string into parts upon a regular expression? That's exactly what "split" is for.

You can get rid of the beginning "" with shift(@arr) if you need to, but it's real -- ditch it and you're effectively changing the number of RR45's found.
# 9  
Old 12-02-2014
Not regex, but one way would be:
Code:
awk -F'RR45' '{for(i=1; i<=NF; i++) if($i~/./) print $i}'

Code:
zghs46
ab57cd
efghRR4ij@klm
vw27z@xyR

--edit--
With perl this could work:
Code:
perl -pe 's/(^|RR45)(.+?)(?=RR45|$)/$2\n/g; s/(RR45)?\n$//'

-or-
Or perhaps simply:
Code:
perl -pe 's/RR45/\n/g; s/^\n|\n$//'

Last edited by Scrutinizer; 12-03-2014 at 02:07 AM..
# 10  
Old 12-03-2014
Hello Corona,

Many thanks for your suggestions and help.

Hello Scrutinizer,

Both solutions work so fine and I've seen your regex that works in other but efective way.

Many thanks to both.

Regards
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