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How to compare specific digit in number?

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# 1  
Old 09-06-2014
How to compare specific digit in number?
Dear All,

Lets say I have a number with following format:
Code:
####.12e-##

now I want to compare place holder in position 1 and 2.
How can I do that?

Note: My number is stored in a variable say var.
example:
Code:
var=9999.12e-05


Thanks & Regards,
linuxUser_
# 2  
Old 09-06-2014
Which OS and shell are you intending to use?

What have you attempted so far?

Is there always going to be a decimal point before the comparison checking?

But most of all please show what you have tried...
# 3  
Old 09-06-2014
Hi,

Thanks for your reply.

I am using bash.
I am completely dumb in this problem. So sorry I haven't tried anything so far.

All I need is how can I compare a number based on their place holders.

example:
Lets say I want to compare 1234 with 4321 or 12w3 with 3hh5
How can I access 1st or 2nd or 3rd ... place holders in that number or something fancy like 12ew.r44.

Just give me simple example.

Most impotently, my number is stored in a variable like var(var=12ew.r44 say).
# 4  
Old 09-06-2014
Use bash's parameter substring expansion: echo ${var:6:2}.
This User Gave Thanks to RudiC For This Post:
linuxUser_
# 5  
Old 09-06-2014
Manually in OSX 10.7.5, default bash terminal:-
Code:
Last login: Sat Sep  6 20:31:06 on ttys000
AMIGA:barrywalker~> SOME_STRING="1234ksj  dflkjsdf 9398 7492834.9198  91283kfc"
AMIGA:barrywalker~> POSITION=3
AMIGA:barrywalker~> NUMBER_OF_CHARACTERS=1
AMIGA:barrywalker~> echo "${SOME_STRING:$POSITION:$NUMBER_OF_CHARACTERS}"
4
AMIGA:barrywalker~> _

This User Gave Thanks to wisecracker For This Post:
linuxUser_
# 6  
Old 09-06-2014
One more help. How can I remove a specific place holder form string?
Example:
Code:
0r2345.r123

so in 7th place r is there.
desired O/P
Code:
0r2345.123

# 7  
Old 09-06-2014
Manually again as before:-
Code:
Last login: Sat Sep  6 20:44:43 on ttys000
AMIGA:barrywalker~> VAR="0r2345.r123"
AMIGA:barrywalker~> echo "${VAR:0:7}${VAR:8:3}"
0r2345.123
AMIGA:barrywalker~> _

EDIT:
Remember, the string always starts at position 0, zero, NOT 1, so it is the 7th subscript or 8th character...
This User Gave Thanks to wisecracker For This Post:
linuxUser_
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