Shell Programming and Scripting

Hi All,

i have a requirement, that script should take inputs/arguments from a file.

1. There is already a script which will ask for input for execution of next step, say: date, reason. name etc....
2. I dont have read or write access to this script just execute permissions.


I tried using basic while loop but it is not helping me. below is the code.

Code:

 echo " Starting WAM "
while read a
do 
/usr/local/wam/start.sh 
echo " $a "   # placed for testing purpose
done < input.txt

please help.

Thanks in advance !!

Hi,
from above, my understanding is that u need to pass arguments to "/usr/local/wam/start.sh" script. your code looks fine, u would change like this

Code:

echo " Starting WAM "
while read a
do 
  /usr/local/wam/start.sh $a
  echo " $a "   # placed for testing purpose
done < input.txt

But if script needs more input then you need to parse values in $a variable and pass them to it.
can you show how the values are in input.txt file??

Thanks,

The for replying newbieabc..
My input.txt will contain
1. Reason for running script... generally a line
2. Current date.
3. Numerical value say 2
Script will first take the first input... will update in some log ( am not sure where it gets updated) ..
Same with other inputs also. ..

I dont see how you expect to run a script you cant read...

Hi vbe.. that script is maintained by my client. . And we are operation team .. so they gave our group execute permission..
We just need to run the script

If your script is one that is expected to run in interactive mode: Since its will ask to enter things (and then read the input after pressing Enter Key...) I dont see how you will be able to get it to accept values, and we cant help without seeing the script...
You best bet is to use expect utility, search the forum for expect usage