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Shell Programming and Scripting

Parsing Column Values in Row

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# 8  
Old 04-28-2014
Quote:
Originally Posted by RudiC
Try sth like (untested)
Code:
awk '/xxxxxxxxx/ {if (L) {print O; O=""; L=0}; O=O substr($0, length($0))}
     /yyyyyyyyy/ {if (!L) {O=O" "; L=1}; O=O substr($0, length($0))}
     END         {print O}
    ' file

Hi Rudic,
can u plz explain the Code, i am not able to make out the meaning of L & Os ...Smilie

BR//
# 9  
Old 04-28-2014
L is a variable he sets himself, to turn printing on and off.

O is a variable which is all the data you want jammed together.
This User Gave Thanks to Corona688 For This Post:
newageBATMAN
# 10  
Old 04-28-2014
Thanks ...Solved
Quote:
Originally Posted by Corona688
L is a variable he sets himself, to turn printing on and off.

O is a variable which is all the data you want jammed together.
Rudic's code worked, being new to awk, i thought L & O to be some sort of Inbuilt variable carrying some special meaningSmilie.

Thanks to both Rudic & Corona for Support ...Smilie
# 11  
Old 04-29-2014
Quote:
Originally Posted by Makarand Dodmis
Hi RudiC

could you please explain above caommand?
Code:
awk '/xxxxxxxxx/ {if (L) {print O; O=""; L=0}; O=O substr($0, length($0))}      # for all lines having the xxx pattern
                                                                                #   if L(ogical) is set, print the output line, clear it, reset L
                                                                                #   collect last char into O(utput) variable
     /yyyyyyyyy/ {if (!L) {O=O" "; L=1}; O=O substr($0, length($0))}            # for yyy pattern
                                                                                #   if not L (= first yyy pattern), add a space for separator to O, set L 
                                                                                #   collect last char as well
     END         {print O}                                                      # print the O(utput) for the last record
    ' file
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