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How to select bulk of info from log file?

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# 1  
Old 03-30-2014
Code How to select bulk of info from log file?
unix : sun
shell : bash

i need to select multiple rows with this format :
Code:
<special format>
10 lines
/<special format>

from log file that have lots of info

i thought of getting the number of the first line using
Code:
grep -n "special format" file | cut -d: -f1

then pass it to shell array and then i will use
Code:
sed -n  a, a+11

to list the rows that i need


the output needed to be like
Code:
<special format>
10 lines
/<special format>
<special format>
10 lines
/<special format>
etc


thanks in advance
Last edited by Scrutinizer; 03-30-2014 at 12:34 PM.. Reason: code tags
# 2  
Old 03-30-2014
Sure it is /<special format>?
Try
Code:
sed -n '/<special format>/,/\/<special format>/p' file
or
awk '/<special format>/,/\/<special format>/' file

# 3  
Old 04-02-2014
Works like a charm
thanks for the info man . it worked just nice
i would add something i found while searching in my case

in order to use sed -n using numbers from shell array which consider it as string value use this format

for i in ${myarray[@]} ; do sed -n $(($i)),$(($i +(number of rows you want to select after line $i)) file ; done
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