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Shell Programming and Scripting

What could be the issue ?

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Top Forums Shell Programming and Scripting What could be the issue ?
# 8  
Old 03-17-2014
It looks like your examples are a bit screwed up.
Is the script name fr.sh or alterNamelist.sh?
Is the second parameter ($2) MQ123 or HOME_NL_NAMES?
Anyway, the following might be closer to what you want:

Code:
#!/bin/ksh
if [ $# != 3 ]
then
echo usage: alterNamelist.sh QMGR MQREQ NAME
fi

#NL=`echo 'dis qmgr'|runmqsc $1|grep REPOSNL|sed 's/.*REPOSNL\(.*\).*/\1/' |cut -d'(' -f2|cut -d')' -f1`
#shorter, all in sed:
NL=`echo 'dis qmgr' | runmqsc $1 | sed -n 's/.*REPOSNL[^(]*(\([^)]*\)).*/\1/p'`

# Backup
echo 'define NAMELIST('$NL'_'$2') like('$NL')'|runmqsc -e $1

# Alter with $3
echo 'dis nl('$NL') names ' | runmqsc $1 | awk '
$1~/^NAMELIST ?\(/ {nl=$0}
$1~/^NAMES ?\(/ {a=1}
a==1 {
  s0=s0 $0
  if (/\)/) {
    sub("\)",","add"\)",s0)
    print "alter",nl,s0
    exit
  }
}' add="$3"

# 9  
Old 03-18-2014
Yes both are same scripts.

When i run below code i got error.

Code:
#!/bin/ksh
if [ $# != 3 ]
then
echo usage: alterNamelist.sh QMGR MQREQ NAME
fi

NL=`echo 'dis qmgr'|runmqsc $1|grep REPOSNL|sed 's/.*REPOSNL\(.*\).*/\1/' |cut -d'(' -f2|cut -d')' -f1`

echo 'define nl('$NL'_'$2') like('$NL')'|runmqsc -e $1

echo 'dis nl('$NL') names ' | runmqsc $1 | awk '
$1~/^NAMELIST ?\(/ {nl=$0}
$1~/^NAMES ?\(/ {a=1}
a==1 {
  s0=s0 $0
  if (/\)/) {
    sub("\)",","add"\)",s0)
    print "alter",nl,s0
    exit
  }
}' add="$3

i got error
Quote:
./fu.sh[11]: syntax error at line 21 : `"' unmatched
i removed " in last line of code and tried i got below error

Quote:
No commands have a syntax error.
One valid MQSC command could not be processed.
awk: syntax error near line 6
awk: illegal statement near line 6
awk: syntax error near line 7
awk: illegal statement near line 7
awk: syntax error near line 11
awk: bailing out near line 11
This User Gave Thanks to darling For This Post:
tahaosman75@gma
# 10  
Old 03-18-2014
You missed the very last "!
Also, in Solaris the awk in /usr/bin/ is broken, please use nawk or /usr/xpg4/bin/awk
# 11  
Old 03-18-2014
I modified as you suggested like below

Code:
#!/bin/ksh
if [ $# != 3 ]
then
echo usage: alterNamelist.sh QMGR MQREQ NAME
fi

NL=`echo 'dis qmgr'|runmqsc $1|grep REPOSNL|sed 's/.*REPOSNL\(.*\).*/\1/' |cut -d'(' -f2|cut -d')' -f1`

echo 'define nl('$NL'_'$2') like('$NL')'|runmqsc -e $1

echo 'dis nl('$NL') names ' | runmqsc $1 | nawk '
$1~/^NAMELIST ?\(/ {nl=$0}
$1~/^NAMES ?\(/ {a=1}
a==1 {
  s0=s0 $0
  if (/\)/) {
    sub("\)",","add"\)",s0)
    print "alter",nl,s0
    exit
  }
}' add="$3"

now i am getting below error

Quote:
nawk: illegal primary in regular expression ) at
source line number 7
context is
>>> sub("\)",","add"\)",s0) <<<
# 12  
Old 03-18-2014
Oops, looks I have hit a bug in nawk.
Use /usr/xpg4/bin/awk, or change the line
Code:
       sub("\)",","add"\)",s0)

to
Code:
       sub( /\)/, ","add"\)", s0 )

# 13  
Old 03-18-2014
i am getting below error.

Quote:
nawk: syntax error at source line 8
context is
sub( /\)/, ","add"\)", s0 >>>
<<<
nawk: illegal statement at source line 8
missing )
code is

Code:
#!/bin/ksh
if [ $# != 3 ]
then
echo usage: alterNamelist.sh QMGR MQREQ NAME
fi

NL=`echo 'dis qmgr'|runmqsc $1|grep REPOSNL|sed 's/.*REPOSNL\(.*\).*/\1/' |cut -d'(' -f2|cut -d')' -f1`

echo 'define nl('$NL'_'$2') like('$NL')'|runmqsc -e $1

echo 'dis nl('$NL') names ' | runmqsc $1 | nawk '
$1~/^NAMELIST ?\(/ {nl=$0}
$1~/^NAMES ?\(/ {a=1}
a==1 {
  s0=s0 $0
  if (/\)/) {
sub( /\)/, ","add"\)", s0
print "alter",nl,s0
    exit
  }
}' add="$3"

# 14  
Old 03-18-2014
Now you are missing the closing ) at the end of the line.
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