Shell Programming and Scripting

Hello,
I am attempting to ssh to a server and run a set of commands on a remote set of servers. I am getting the following error below, I am thinking quotes may be the problem. This command works on the local machine in bash. Not when I ssh to a remote server. Basically the command should replace a portion of a string in /etc/rc.local then kill a process, then using the replaced string in rc.local use grep to set a variable (the first half of the string is different on servers) to run it.

Hope that is explained well enough.


ERROR:
This happens only when I use ssh to remote server.

Code:

 bash: -c: line 1: syntax error: unexpected end of file

Command:

Code:

#!/bin/bash
for server in server1 server2 
do
ssh -l user $server "/bin/sed -i 's/_prod/_DFLT/' /etc/rc.local && /usr/bin/pkill ptpd && x=$(grep ptpd /etc/rc.local) && $x"

done

Embedding the remote code in local code denotes a second evaluation.
Instead have the script code in a separate file script.sh and run it remotely with

Code:

for server in server1 server2
do
ssh -qx -l user $server "sh -s" < script.sh
done

Arguments can can be passed after the -s.

Run that line with the -x option set to see what causes the trouble. It may be sufficient to escape the $ signs.

Thanks to your replies, I ended up using the \$ method which worked.