Shell Programming and Scripting

I am embedding bash in cpp. Can the bash code be hidden (when we cat the executable to not be able to see the bash code)
The simple code I am using:
#include <iostream>
#include <cstdlib>
using namespace std;


#define test1 "\
#!/bin/sh --posix \n\
echo \"2222222222222222222222222222222222222222222222222222\" \n\
"


int main()
{

system(test1);
return 0;

}

You cannot because, no matter how you hide it, when you run it, it will feed the complete unencrypted text into the shell. It has to, or else system() couldn't run it!

That is always the problem with rube goldberg solutions. The code will always still be there, and has to contain all the necessary steps for decrypting itself in plain, or it won't work.

Adding more hoops will not help, since they can ignore everything but the last "hoop" -- the shell.

We have been down this road many, many, many times before. There is no magic solution to keeping running code protected on a system you do not trust, by definition. The system must have the unencrypted code, and if you can't trust the system, there's nothing left to protect you. Your real options remain as I gave them in the thread you crossposted this question from.